Answer:
Let x and y be the two numbers. Then
yx=57 and x−y=20
Cross multiplying the proportion
5x=7y or y=75x
So, x−y=20
x−75x=20⇒77x−5x=72x=20
⇒x=2140=70
y=75x=75×70=50
So smaller number is 50.
Check :yx=5070=57 and 70−50=20
<span>If you tripled the slant height and radius of a cone, the
formula to find the modified surface area would be 6 and 6. I am hoping that this
answer has satisfied your query about and it will be able to help you, and feel
free to ask another question if you’d like.</span>
B = 3h . . . . . . . .given by the problem statement
A = (1/2)bh . . . . formula for the area of a triangle
486 cm² = (1/2)*(3h)*h . . . substitute given information
(2/3)*486 cm² = h² . . . . . .multiply by 2/3
√324 cm = h . . . . . . . . . . . . . .take the square root
The height is 18 cm.
The base is 3*18 = 54 cm.
Answer:
Step-by-step explanation:
It's algebra really, basically make a system of equations.
1b+5j=t
3b+2j=2t
I'm gonna solve the first one for buckets so we have it in terms of jars.
b+5j=t
b=t-5j
Now I plug that into the other equation
3b+2j=2t
3(t-5j)+2j=2t
3t-15j+2j=2t
Now, since it wants how many jars are in one tub, I want to solve it so there's 1t on one side of the equation and all js on the other. or it other words solve for t.
3t-15j+2j=2t
3t-13j = 2t
3t = 2t+13j
t = 13j
So it takes 13 jars to make one tub, or one jar is 1/13 of a tub. You could then plug that in to one of the equations and find how much a bucket is.
