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Mrrafil [7]
3 years ago
11

I need help with this question​

Mathematics
1 answer:
Artyom0805 [142]3 years ago
5 0

Answer:

Step-by-step explanation:

It's algebra really, basically make a system of equations.

1b+5j=t

3b+2j=2t

I'm gonna solve the first one for buckets so we have it in terms of jars.

b+5j=t

b=t-5j

Now I plug that into the other equation

3b+2j=2t

3(t-5j)+2j=2t

3t-15j+2j=2t

Now, since it wants how many jars are in one tub, I want to solve it so there's 1t on one side of the equation and all js on the other.  or it other words solve for t.

3t-15j+2j=2t

3t-13j = 2t

3t = 2t+13j

t = 13j

So it takes 13 jars to make one tub, or one jar is 1/13 of a tub.  You could then plug that in to one of the equations and find how much a  bucket is.  

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Answer: Choice B

Range = {-3, 1, 5}

============================================

Explanation:

The domain is the set of all possible input x values. The range is the set of all possible y outputs.

Plug in each x value from the domain, one at a time, to get its corresponding range y value.

--------------------

Start with x = -3

f(x) = 2x+3

f(-3) = 2(-3)+3

f(-3) = -6+3

f(-3) = -3

So -3 is in the range.

--------------------

Move onto x = -1

f(x) = 2x+3

f(-1) = 2(-1)+3

f(-1) = -2+3

f(-1) = 1

1 is also in the range

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Finally plug in x = 1

f(x) = 2x+3

f(1) = 2(1)+3

f(1) = 2+3

f(1) = 5

The value 5 is the final value in the range.

--------------------

All of those values form the set {-3, 1, 5} which is the complete range.

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Final grades are often computed using weighted averages. For example, Fran's teacher uses the following: homework 10%, quizzes 2
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The final grade of fran can be calculated by multiplying the corresponding percentage of his average homework, quizzes and tests, then sum it up and it is now the final grade of fran.

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<span>Final grade = 79.5 </span>

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Solve the following system using elimination:

{5 y - 2 x = -42 | (equation 1)

7 x + 2 y = 30 | (equation 2)

Swap equation 1 with equation 2:

{7 x + 2 y = 30 | (equation 1)

-(2 x) + 5 y = -42 | (equation 2)

Add 2/7 × (equation 1) to equation 2:

{7 x + 2 y = 30 | (equation 1)

0 x+(39 y)/7 = (-234)/7 | (equation 2)

Multiply equation 2 by 7/39:

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Subtract 2 × (equation 2) from equation 1:

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