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2 years ago

I need help with this question

Mathematics

1 answer:

Artyom0805 [142]2 years ago

5 0

Answer:

Step-by-step explanation:

It's algebra really, basically make a system of equations.

1b+5j=t

3b+2j=2t

I'm gonna solve the first one for buckets so we have it in terms of jars.

b+5j=t

b=t-5j

Now I plug that into the other equation

3b+2j=2t

3(t-5j)+2j=2t

3t-15j+2j=2t

Now, since it wants how many jars are in one tub, I want to solve it so there's 1t on one side of the equation and all js on the other. or it other words solve for t.

3t-15j+2j=2t

3t-13j = 2t

3t = 2t+13j

t = 13j

So it takes 13 jars to make one tub, or one jar is 1/13 of a tub. You could then plug that in to one of the equations and find how much a bucket is.

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Can someone answer i put brainliest and 13 points

Arturiano [62]

Answer:

Well the first digit of the quotient for 6,139 / by 153 can go in between 1 and 3

Step-by-step explanation:

I hope this helps now have a good and blessed day

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1 year ago

What is the solution to the equation?

Gelneren [198K]

Answer:

Hello,

answer B

Step-by-step explanation:

$\dfrac{2}{x} -\dfrac{x}{x+5} =\dfrac{10}{x^2+5x} \\\\we\ suppose\ x\neq 0\ and\ x\neq -5\\\\\text{Reducing to the same denominator}\\\dfrac{2(x+5)-x^2}{x(x+5)} =\dfrac{10}{x^2+5x} \\\\Simplify\ by\ x^2+5x\\\\2x+10-x^2=10\\\\-x^2+2x=0\\\\-x(x-2)=0\\\\roots\ are\ 2 \ and\ 0\ (to\ be\ excluded)\\\\Root=2\\$

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2 years ago

The trip took 1 hour and 40 minutes 30% of the time the car traveled on rough roads how much time did the car travel on rough ro

Effectus [21]

Answer:

NOTE: 1 HOUR IS 60 MINUTES

do 60+40 gives u the minute which is 100

then 100 x30% = 30

NOTE: for the second round up the digit and multiply it by 65

so 40.4 x 65 gives 62. something

the nearest number is 60 % so 60% is the answer

<em>Please mark as brainliest</em>

Have a great day, be safe and healthy

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2 years ago

Read 2 more answers

If y varies directly with x, and y = 10 when x = 4, write the direct linear variation equation

torisob [31]

The answer is c. I chose the answer c because y=5/2x(I think you forgot to put the x in the question) filled in with the numbers are true while a, b, and d aren't true if filled with 10 and 4.

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2 years ago

Read 2 more answers

A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successi

My name is Ann [436]

Answer:

option C

c. least: $101

greatest: $1001

Step-by-step explanation:

A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.

Sum of 10 prizes = 5510

100 is the difference. there is a common difference d=100

So its a arithmetic sequence

the sum formula for arithmetic sequence is

$S_n = \frac{n}{2}(2a_1 +(n-1)d)$

Sn = 5510, n=10 n d= 100 we need to find out first term a1

$5510 = \frac{10}{2}(2a_1 +(10-1)100)$

5510 = 5 (2a1 + 900)

5510 = 10a1 + 4500

Subtract 4500 on both sides

1010= 10a1

divide by 10 on both sides

a1 = 101

so first term that is least term is 101

To find out greatest term we use formula

$a_n = a_1 + (n-1) d$

a(10) = 101 + (10-1)100

= 101 + 900= 1001

greatest is 1001

4 0

3 years ago

I need help with this question​

I need help with this question