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Rom4ik [11]
3 years ago
15

Um what is the answer to this picture right here .

Mathematics
1 answer:
algol133 years ago
4 0

Answer: D

Step-by-step explanation:

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An electrician needs to buy 12 3/5 yards of electrical wire. Wire is sold on spools that have 3 1/2 yards of wire in each. How m
qwelly [4]
He needs to buy 3.6 spools but I guess that wouldn't be possible in real life so he needs to get 4 and then has some leftover.
12 3/5 / 3 1/2 = 3.6
6 0
3 years ago
Three cities form a right triangle on a map. Cities B and C are the furthest apart. If cities A and B are 14 miles apart And cit
nekit [7.7K]

Answer:

26.1miles

Step-by-step explanation:

If three cities A, B and C form a right triangle on a map, and the Cities B and C are the furthest apart, then the distance between cities B and C will be the hypotenuse of the triangle.

If cities A and B are 14 miles apart, then |AB| = 14miles

Also if cities A and C are 22 miles apart, then |AC| = 22miles.

To get |BC| which is the distance between cities B and C, we will use the Pythagoras theorem.

|BC|² = |AB|² + |AC|²

|BC|² = 14²+22²

|BC|² = 196+484

|BC|² = 680

|BC| = √680

|BC| = 26.1miles

This means that cities B and C are 26.1miles apart

7 0
3 years ago
Convert 945 in/sec to miles per hour. round to one decimal​
Ulleksa [173]

Answer:

53.7 miles per hour

divide the speed value by 17.6

6 0
3 years ago
Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s
Snezhnost [94]

Answer. First option: t > 6.25


Solution:

Height (in feet): h=-16t^2+729

For which interval of time is h less than 104 feet above the ground?

h < 104

Replacing h for -16t^2+729

-16t^2+729 < 104

Solving for h: Subtracting 729 both sides of the inequality:

-16t^2+729-729 < 104-729

-16t^2 < -625

Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

16t^2 > 625

Dividing both sides of the inequality by 16:

16t^2/16 > 625/16

t^2 > 39.0625

Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25



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The reflection of the point (4, 6) over the y-axis is:
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(-4,6)
The x value changes bc since it is a reflection y cannot change and x becomes negative
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