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Rom4ik [11]
3 years ago
15

Um what is the answer to this picture right here .

Mathematics
1 answer:
algol133 years ago
4 0

Answer: D

Step-by-step explanation:

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(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounde
monitta

Using the distance formula, d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\, what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?

Using the points given, plug them into the equation.

d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\d = \sqrt{((4) - (-2))^2 + ((4) - (2)^2  } \\d=\sqrt{(4+2)^2 + (4-2)^2}\\d=\sqrt{(6)^2 + (2)^2}  \\d=\sqrt{36+4} \\d=\sqrt{40} \\

Plug this into a calculator and you get 6.32455532

Since you only need it up to the tenth (0.1), round up 6.32

<em>Five or more, let it soar. Four or less, let it rest.</em>

Since two is lower than four, we drop it.

Therefore, the distance between points (-2, 2) and (4, 4) is 6.3

Hope this helps ^w^

8 0
2 years ago
Identify the vertex of the function, fx) = 3(x - 1)2 + 5.
madam [21]

Answer:

fx) = 3x+4

Step-by-step explanation:

1. step:

solve the bracket

fx) = 3(x - 1) 2 + 5

fx) = 3x-1+2+5

2. step:

use the BEDMAS form.

fx) = 3x-3+7

fx) = 3x+4

8 0
3 years ago
What is the width of a rectangle with a length of 14 cm and an area of 161 cm squared
mestny [16]
Area of a rectangle=length×width. If the area is 161 and the length is 14 then that means: 161=14×width. You would then divide 161÷14 and you will find that the width is 11.5. 
8 0
3 years ago
Help plssss!!!!!! I really need help
Andrews [41]

The answer for the following question is option A.

3 0
2 years ago
Read 2 more answers
Add: (–6 – n + 2n2) + (8 – 3n – 10n2)
MArishka [77]
The answer is C:
2-4n-8n^2

you add the variables with the same exponents and the constants in (-6-n+2n^2) + (8-3n-10n^2).

4 0
3 years ago
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