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Goshia [24]
3 years ago
12

A large University accepts 70%of the students who apply. Of the students the university accepts, 50% actually enroll. If 20,000

students apply, how many actually enroll?
Mathematics
2 answers:
olchik [2.2K]3 years ago
7 0
Out of 20000 only 7000 will actually enroll.
Hope this helps.
Anarel [89]3 years ago
5 0

Answer:

<em>7,000 students</em>

Step-by-step explanation:

Since 20,000 applied  to the university you have to find 70% of 20,000.

<u>20,000 × 70% = </u><u>14,000</u><u>.</u>

Then you find 50% of 14,000 because 50% acually enroll to the university.

<u>14,000 × 50%</u><u> </u><u>=</u><u> </u><em><u>7,000</u></em>

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lorasvet [3.4K]

Answer:

the answer to this one is A.

Step-by-step explanation:

3 0
3 years ago
a motorboat travels 305km in 5 hours going upstream and 651km in 7 hours going downstream. What is the rate of the boat in still
Ghella [55]
Recall your d = rt, distance = rate * time.

b = speed rate of the boat.

c = speed rate of the current.


keeping in mind that, as the boat goes Upstream, against the current, it's speed is not "b", but is really " b - c ", because the current is subtracting speed from it.

likewise, when the boat is going Downstream, because is going with the current, is really going faster at " b + c ".

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what is the speed of the boat?  well, 61 + c = b.
6 0
4 years ago
Help me with this please
Nataliya [291]
Answer:1/2
Explanation
8 0
3 years ago
Read 2 more answers
Let the sample size of leg strengths to be 7 and the sample mean and sample standard deviation be 630 watts and 32 watts, respec
Colt1911 [192]

Answer:

a. There is_<u><em>sufficient</em></u> evidence that the leg

C. 0.010 < P-value < 0.025

b. Power of test = 1- β=0.2066

c. So the sample size is 88

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0 : u1= u2 against Ha : u1 > u2 This is a right tailed test

Here n= 7 and significance level ∝= 0.005

Critical value for a right tailed test with 6 df is 1.9432

Sample Standard deviation = s= 32

Sample size= n= 7

Sample Mean =x`= 630

Degrees of freedom = df = n-1= 7-1= 6

The test statistic used here is

Z = x- x`/ s/√n

Z= 630-600 / 32 / √7

Z= 2.4797= 2.48

P- value = 0.0023890 > ∝ reject the null hypothesis.

so it lies between 0.010 < P-value < 0.025

b) Power of test if true strength is 610 watts.

For  a right tailed test value of z is = ± 1.645

P (type II error) β= P (Z< Z∝-x- x`/ s/√n)

Z = x- x`/ s/√n

Z= 610-630 / 32 / √7

Z=0.826

P (type II error) β= P (Z< 1.645-0.826)

= P (Z> 0.818)

= 0.7933

Power of test = 1- β=0.2066

(c)

true mean = 610

hypothesis mean = 600

standard deviation= 32

power = β=0.9

Z∝= 1.645

Zβ= 1.282

Sample size needed

n=( (Z∝ +Zβ )*s/ SE)²

n=  ((1.645+1.282) 32/ 10)²

Putting the values  and solving we get 87.69

So the sample size is 88

5 0
3 years ago
The Australian sheep dog is a breed renowned for its intelligence and work ethic. It is estimated that 45% of adult Australian s
ArbitrLikvidat [17]

Answer:

Probability of more than 9 adult Australian sheep dogs out of 12 weighing 65 lb or more

P(X > 9) = 0.00788

Step-by-step explanation:

The only assumption required for the question is that all 12 adult dogs sampled must all be Australian sheep dogs.

This is a binomial distribution problem

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of adult dogs to be sampled = 12

x = Number of successes required = number of dogs that weigh 65 lb or more

= more than 9; >9

p = probability of success = probability of a dog weighing 65 lb or more = 0.45

q = probability of failure = probability of a dog NOT weighing 65 lb or more = 1 - 0.45 = 0.55

P(X > 9) = P(X=10) + P(X=11) + P(X=12)

Solving each of these probabilities, using the binomial distribution formula

P(X = x) = ¹²Cₓ (0.45)ˣ (0.55)¹²⁻ˣ with x = 10, 11 and 12

P(X > 9) = P(X=10) + P(X=11) + P(X=12)

= 0.00679820806 + 0.00101130368 + 0.00006895252

= 0.00787846427

= 0.00788 to 3 s.f

Hope this Helps!!!

3 0
3 years ago
Read 2 more answers
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