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arsen [322]
3 years ago
8

Michael is twice as old as Ann. If 14 is added to Ann’s age and 22 is subtracted from Michael’s age, their ages will be equal. W

hat are their present ages?
Mathematics
1 answer:
Digiron [165]3 years ago
5 0

Answer: Michael is 72 while Ann is 36.

Step-by-step explanation: Let X represent Michael's age and Y represent Ann's. From the first sentence,

Y=2X. (eqn 1)

14+X=Y-22 (eqn 2)

X-Y=-22-14

X-Y=-36; But Y=2X.

Therefore, X-2X=-36; -X=-36; X=36. Hence, Y=2*36; Y=72.

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Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e
saw5 [17]

Answer:

A straight line of approximately 75 meters, 1.4º north

Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in R^{2}. To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.  

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle

Now, let's calculate each vector length by calculating the norm.

\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

8 0
3 years ago
Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg lesss strawberries in the morning tha in the afte
Tpy6a [65]

Answer:

3\frac{13}{20}=3.65 kg.

Step-by-step explanation:        

Let S be amount of strawberries picked in the afternoon.

We have been given that Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the afternoon and the strawberries picked in morning are 2\frac{1}{4} kg.

To find the amount of strawberries picked by Sheldon in the afternoon we will add 2\frac{1}{4} and 1\frac{2}{5}  :

S= 2\frac{1}{4}+1\frac{2}{5}      

Upon converting our given mixed fractions into improper fraction we will get,

S= \frac{9}{4}+\frac{7}{5}

Now let us have a common denominator.

S=\frac{9*5}{4*5}+\frac{7*4}{5*4}

S=\frac{45}{20}+\frac{28}{20}

S=\frac{45+28}{20}

S=\frac{73}{20}  

S=3\frac{13}{20}  

S=3.65

Therefore, Sheldon picked 3\frac{13}{20}=3.65 kg of strawberries in the afternoon.  

3 0
3 years ago
What is (-94)÷5+22÷22's square?
Paha777 [63]

Answer:

Error

Step-by-step explanation:

(-94)/5+22/22    Given

-18.8+1                PEMDAS (do -94/5 and 22/2)

-17.8                    Add the numbers

After you add the numbers, you take the square root. you will get the answer "Error" because you cannot take the square root of a negative number

5 0
3 years ago
Simplify the following rational expression and state for what values they are undefined.
QveST [7]

Answer:

d-2  and d cannot = 8

Step-by-step explanation:

d^2 -10d+16

-----------------------

d-8

Factor the numerator

( d-8)(d-2)

-------------------

d-8

The undefined values occur when the denominator is equal to zero

d-8 = 0  

  d= 8

This means d cannot equal 8

Now cancel like terms in the equation ( d-8)

This yields d-2

3 0
3 years ago
Read 2 more answers
On Friday, 278 fourth graders went on a field trip to the Arizona State museum. The staff divided them into 7 tour groups. Which
stiks02 [169]
There would be ABOUT 40 kids in each group :-)

6 0
3 years ago
Read 2 more answers
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