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Westkost [7]
2 years ago
5

A student completes 2/5 of a science project in 3/4 hour. At this rate, what fraction of the project can the student complete pe

r hour?
Mathematics
1 answer:
kvasek [131]2 years ago
4 0

The fraction of the fence completed in one hour at a rate of  \frac{2}{5} of the

fence in  \frac{3}{4} hours is  \frac{8}{15}.

<h3>How can the fraction completed in one hour be found?</h3>

The fraction of the fence completed in \mathbf{\frac{3}{4}} of an hour = \frac{2}{5}

Required:

The fraction of the fence the student completes per hour;

Solution;

The time \mathbf{\frac{2}{5}} of the fence is completed =  \frac{3}{4} of an hour

Therefore;

The \ in \ \mathbf{\frac{\dfrac{3}{4} \ hour}{\dfrac{3}{4} \ hour}}  = 1 \ hour \ the \ frraction \ completed = \dfrac{\dfrac{2}{5} }{\dfrac{3}{4} \ hour}  = \dfrac{8}{15} \ per \ hour

The fraction of the fence completed per hour = \underline{\frac{8}{15}}

Learn more about fractions here:

brainly.com/question/21339546

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<h3>Further explanation</h3>

There are several forms of transformation, including translation, dilation, rotation or reflection

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\left[\begin{array}{ccc}x'\\y'\end{array}\right]=\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4-6\\1+1\end{array}\right]+\left[\begin{array}{ccc}6\\-1\end{array}\right]\\\\=\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}-2\\2\end{array}\right]+\left[\begin{array}{ccc}6\\-1\end{array}\right]\\\\=\left[\begin{array}{ccc}8\\1\end{array}\right]

2. translation (0,2)

\left[\begin{array}{ccc}8\\1\end{array}\right]+\left[\begin{array}{ccc}0\\2\end{array}\right]=\left[\begin{array}{ccc}8\\3\end{array}\right]

<h3 /><h3>Learn more</h3>

brainly.com/question/13715226

Keywords: transformation, translation, rotation

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