Assuming that the figures given are square such that the scale factor between them is equal to 28/8 which can be further simplified into 7/2. The ratio of the perimeter is also equal to this value, 7/2. However, the ratio of the areas is equal to the square of this value giving us an answer of 49/4.
Answers:
10.) 
9.) 
8.) 
7.) 
6.) 
Step-by-step explanations:
10.) 
9.) ![\displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Csqrt%5B3%5D%7B135%7D%7D%7B%5Csqrt%5B3%5D%7B40%7D%7D%20%5Chookrightarrow%20%5Csqrt%5B3%5D%7B3%5Cfrac%7B3%7D%7B8%7D%7D%20%5Chookrightarrow%20%5Cfrac%7B3%5Csqrt%5B3%5D%7B5%7D%7D%7B2%5Csqrt%5B3%5D%7B5%7D%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B1%5Cfrac%7B1%7D%7B2%7D%7D)
8.) ![\displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Csqrt%5B4%5D%7B162%7D%7D%7B%5Csqrt%5B4%5D%7B32%7D%7D%20%5Chookrightarrow%20%5Csqrt%5B4%5D%7B5%5Cfrac%7B1%7D%7B16%7D%7D%20%5Chookrightarrow%20%5Cfrac%7B%5Cpm%7B3%5Csqrt%5B4%5D%7B2%7D%7D%7D%7B%5Cpm%7B2%5Csqrt%5B4%5D%7B2%7D%7D%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B%5Cpm%7B1%5Cfrac%7B1%7D%7B2%7D%7D%7D)
7.) 
6.) 
I am joyous to assist you at any time.
Hi there!
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I believe your answer is:

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Here’s why:
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
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Hope this helps you. I apologize if it’s incorrect.