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Umnica [9.8K]
2 years ago
9

Which of the following are agricultural industry clusters? Human population systems, computer technoloy biotechnology or food pr

oducts and
Computers and Technology
1 answer:
GalinKa [24]2 years ago
6 0

Biotechnology

Food Products and Processing Systems.

Further explanation

Career clusters help prepare learners with knowledge that they need to use towards achieving their career goals. One such career cluster is the Agriculture, Food, and Natural Resources career cluster which is divided into seven pathways. They include:

  • Food Products and Processing Systems.
  • Biotechnology Systems
  • Agribusiness Systems
  • Plant Systems
  • Animal Science
  • Environmental Service Systems
  • Natural Resource Systems

This brings us to our answers above. Those working in the Food Products and Processing Systems pathway are responsible in discovering new food sources and coming up with ways to process and store food set out by industry regulation. On the other hand, biotechnology systems deal with techniques that use science to solve problems concerning living organisms and anyone thinking about pursuing this pathway ought to demonstrate competence in the application of biotech in the context of Agriculture, Food, and Natural Resources.

Learn about Agriculture, Food, and Natural Resources career cluster

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Answer: i think the answer is

a. Multiple IRRs can occur only if the signs of the cash flows change more than once.

Explanation:

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A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co
tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k  ...(1)

probability of 2 hops = k(1-k)  ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

                                                       = (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

                                                       = k + 2k - 2k² + 3(1 + k² - 2k)

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b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

     ∞                             n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

    n-1

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c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet =  k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet =  k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

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