X + k y = 1
k x + y = 1 / * ( - k )
----------------
x + k y = 1
- k² x - k y = - k
--------------------
x - k² x = 1 - k
x ( 1 - k² ) = 1 - k
x = ( 1 - k ) / ( 1 - k² ) = ( 1 - k ) / ( 1 - k ) ( 1 + k )
y = 1 - k( 1 - k )/( 1 - k² )
y = ( 1 - k ) / ( 1 - k² ) = ( 1 - k ) / ( 1 - k ) ( 1 + k )
a ) For k = - 1 this system has no solution.
b ) For k ≠ - 1 and k ≠ 1, the system has unique solution:
( x , y ) = ( 1/ (1 + k) , 1/( 1 + k ) ).
c ) For k = 1, there are infinitely many solutions.
1/4(8x+56)=20
1/4(8x)+1/4(56)=20
2x+14=20
2x=20-14
2x=6
X=3
Answer:
I don't know the answer but i recommend a website called cymath. It is a calculator to any equation and demonstrates the procedures.
Answer:
A
Step-by-step explanation:
( 2, -5 )
( -2, -5)
Hope this helps dude
