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3 years ago

If 11 boxes of chocolates contain 220 chocolates in total, calculate how many chocolates 5 box of chocolates will contain

Mathematics

1 answer:

egoroff_w [7]3 years ago

4 0

Answer:100 chocolates

Step-by-step explanation:

20 chocolate in each box so 20 time 5 is 100 so 20 time 11 is 220

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Eje cartesiano y=-x+7 2

victus00 [196]

Answer:

Step-by-step explanation:

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2 years ago

Please help with this algebra question

zhenek [66]

We have
-2x-3y <12
For this case what you should do is to graph the following straight line:
-2x-3y = 12
Then, the solution will be the shaded region that satisfies the following inequality:
-2x-3y <12
In the shaded region you will find all the solution points.
Answer:
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3 years ago

A croissant shop produces two products: bear claws (B) and almond filled croissants (C). Each bear claw requires 6 oz of flour,

Kruka [31]

Answer:

letter A: B = 400; C = 1000; Max Z = $380

Step-by-step explanation:

bear claws (B) need 6 oz of flour (f), 1 oz of yeast (y), 2 ts of paste (p)

croissants (C) need 3 oz of flour (f), 1 oz of yeast (y), 4 ts of paste (p)

putting that information in equations, we have:

B = 6f + y + 2p

C = 3f + y + 4p

The total number of resources (R) are:

R = 6600f + 1400y + 4800p

Let's call M our total profit, "k1" the number of B produced and "k2" the number of C produced.

So, we can state that:

M = k1*0.2 + k2*0.3

The number of resources R2 will demand is calculated like this:

R2 = k1*B + k2*C = (6k1+3k2)f + (k1+k2)y + (2k1+4k2)p

using R2 and R, we can make some inequations:

6k1+3k2 <= 6600 -> 2k1+k2 <= 2200

k1+k2 <= 1400

2k1+4k2 <= 4800 -> k1+2k2 <= 2400

if we try to maximize k2 (as it worths more), we will have k1 = 0 and k2 = 1200 (limited by p), but looking at the resources R, we will still have resources to use (f and y). Looking at B and C expressions, we see that removing one C gives enough 'p' to make 2 B, which is a good trade (as 2B worths 0.4 cents, and 1C worths 0.3 cents). we have 200 'y' remaining, so doing this 200 times give us k1 = 400 and k2 = 1000, and the only resource remaining will be some of 'f'.

calculating the profit M, we have:

M = 400*0.2 + 1000*0.3 = 380$

the right answer is letter A.

3 0

3 years ago

Write each number in expanded form and using number names.

stellarik [79]

1. 20,000 +7,000 +500 +40 +9 -----WORD FORM :twenty-seven thousand,
five hundred forty-nine

2. Expanded Numbers Form:

 700,000 +90,000 +2,000 +0 +60 +5 
WORD FORM : seven hundred ninety-two thousand,
sixty-five

3 0

3 years ago

Geometry. Please help ASAP.

neonofarm [45]

Please see the pic, I'd solved your question in it.

6 0

3 years ago