This is a part:part ratio. to solve it we need to convert it into a part:whole ratio. we do this by adding the parts. the ratio of pumpkin cans to total cans is 5:7. 140/7=20. 20x5=100. 20x2=40. The answer is B. 40 cans.
Answer:
![g(x)=-2\sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%3D-2%5Csqrt%5B3%5Dx)
or

Step-by-step explanation:
Given
![f(x) = \sqrt[3]x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5Dx)
Required
Write a rule for g(x)
See attachment for grid
From the attachment, we have:


We can represent g(x) as:

So, we have:
![g(x) = n * \sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%20%3D%20n%20%2A%20%5Csqrt%5B3%5Dx)
For:

![2 = n * \sqrt[3]{-1}](https://tex.z-dn.net/?f=2%20%3D%20n%20%2A%20%5Csqrt%5B3%5D%7B-1%7D)
This gives:

Solve for n


To confirm this value of n, we make use of:

So, we have:
![-2 = n * \sqrt[3]1](https://tex.z-dn.net/?f=-2%20%3D%20n%20%2A%20%5Csqrt%5B3%5D1)
This gives:

Solve for n


Hence:
![g(x) = n * \sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%20%3D%20n%20%2A%20%5Csqrt%5B3%5Dx)
![g(x)=-2\sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%3D-2%5Csqrt%5B3%5Dx)
or:

780 square meters each month 972 kilowatts hourly
RT = 8 , RS = 3 AND ST = 5.4
RV = 4 , RU = 1.5 AND UV = 2.7
∴ RT/RV = 8/4 = 2
AND RS/RU = 3/1.5 = 2
AND ST/UV = 5.4/2.7 = 2
∴Δ RTS IS SIMILAR TO ΔRVU
SO, the best statement is:
Each pair of sides corresponds with a common ratio of 2.
She will pay 20$ for 10 pounds of hamburger