Answer:
The correct option is B. 16.3
Step-by-step explanation:
We are given a vector with components
V = 36x +33y
To solve this problem, we find its magnitude
|V| = SQRT (36^2 + 33^2)
|V| = SQRT (2385)
|V| = 48.836
To find the magnitude of the new vector we divide by three the previous quantity
|V2| = 48.836/3 = 16.278
The value of P(4, 6) when the two number cubes are tossed is 1/36
<h3>How to determine the probability?</h3>
On each number cube, we have:
Sample space = {1, 2, 3, 4, 5, 6}
The individual probabilities are then represented as:
P(4) =1/6
P(6) =1/6
The value of P(4, 6) when the two number cubes are tossed is:
P(4, 6) = P(4) * P(6)
This gives
P(4, 6) = 1/6 * 1/6
Evaluate
P(4, 6) = 1/36
Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36
Read more about probability at:
brainly.com/question/24756209
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It is defined as the difference between the largest and smallest values in the middle 50% of a set of data<span>. To compute an </span>interquartile range<span> using this definition, first remove observations from the lower quartile. Then, remove observations from the upper quartile.</span>
(2n-1) /(n+9)
hope it can help u