Question

Find the value of x in each case: PU ∩ RT = S, Q ∈ PR

Answer 1

Answer:

x=34

Step-by-step explanation:

When we look triangle SQR, we have angles 3x and 68, we know that sum angles of triangle is 180.

<R=180-(3x+68)

Now, we look at the PQS:

<PQS=180-68=112°

Then :

<PSQ=180-(112+x)=68-x

Then we have :

Angles PSR= 68-x+3x=68+2x and angles TSU=4x.

We have that

PSR=TSU

68+2x=4x

4x-2x=68

2x=68

x=34