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belka [17]
4 years ago
14

Suppose air resistance does not exist, roughly what would be the velocity of a 10 lb object 5-seconds into free fall off of a 50

0-m building? How is this answer 50 m/s?
Physics
1 answer:
ira [324]4 years ago
4 0

Answer:

Correct answer :  v = 50 m/s

Explanation:

The movement described is a free fall with no initial velocity and we will use the following formula:

v = g · t   we take that g = 10 m/s²

v = 10 m/s²· 5 s = 50 m/s

v = 50 m/s

God is with you!!!

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What type of energy is a cat lying in a sunny window
cluponka [151]

Answer:

potential energy

Explanation:

Potential refers to stored energy while kinetic is energy in motion

3 0
3 years ago
A baseball has a mass of 0.15 kg and radius 3.7 cm. In a baseball game, a pitcher throws the ball with a substantial spin so tha
mylen [45]

Answer:

Rotational kinetic energy = 0.099 J

Translational kinetic energy = 200 J

The moment of inertia of a solid sphere is I = \frac{2}{5}mr^2.

Explanation:

Rotational kinetic energy is given by

\text{RKE} = \frac{1}{2}I\omega^2

where <em>I</em> is the moment of inertia and <em>ω</em> is the angular speed.

For a solid sphere,

I = \frac{2}{5}mr^2

where <em>m</em> is its mass and <em>r</em> is its radius.

From the question,

<em>ω</em> = 49 rad/s

<em>m</em> = 0.15 kg

<em>r</em> = 3.7 cm = 0.037 m

\text{RKE} = \frac{1}{2}\times \frac{2}{5} mr^2\omega^2 = \frac{1}{5} mr^2\omega^2

\text{RKE} = \frac{1}{5} (0.15\ \text{kg})(0.037\ \text{m})^2(49\ \text{rad/s})^2 = 0.099\text{ J}

Translational kinetic energy is given by

\text{TKE} = \frac{1}{2} mv^2

where <em>v</em> is the linear speed.

\text{TKE} = \frac{1}{2} (0.15\ \text{kg})(52\ \text{m/s})^2 = 200\text{ J}

5 0
3 years ago
Read 2 more answers
Which of the following statements regarding the moon and Earth is correct?
hoa [83]
It’s Definitely A the other one’s are definitely wrong and I know A is a fact
7 0
2 years ago
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 3.00 m above
statuscvo [17]

Answer: The gravitational acceleration near the surface of this planet is 9.056 m/s^2

Explanation:

When you drop an object, the only acceleration acting on the object is the gravitational acceleration, so we can writhe the acceleration of the wrench as

a(t) = -g

where the minus sign is because the wrench will move downwards.

for the velocity of the object, we integrate over time and get:

v(t) = -g*t + v0

where v0 is the initial velocity, in this case is 0, because the wrench is droped.

integrating again, we will get the position of the wrench:

p(t) = -(g/2)*t^2 + p0

where p0 is the initial position, in this case is 3m above the ground.

p(t) = -(g/2)*t^2 + 3m

now, afther 0.814seconds the wrench hits the ground, so we have:

p(0.814 s) = 0 =  -(g/2)*(0.814s)^2 + 3m

now we need to solve this for g.

-(g/2)*(0.814s)^2 + 3m = 0

(g/2)*(0.814s)^2 = 3m  

(g/2) = 3m/*(0.814s)^2 = 4.528m/s^2

g = 2*4.528m/s^2 = 9.056 m/s^2

6 0
3 years ago
How does speed affect momentum
Arada [10]
Momentum = mass • velocity
M = m • v

Speed is a scalar quantity
Velocity is a vector quantity

That is truly the only difference
8 0
3 years ago
Read 2 more answers
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