In the Biomedical and Physical Sciences building at MSU there are 135 steps from the ground floor to the sixth floor. Each step
1 answer:
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Answer:
1.01 × 10⁵ Pa
Explanation:
At the surface, atmospheric pressure is 1.013 × 10⁵ Pa.
We need to find the total pressure on the air in the lungs of a person to a depth of 1 meter.
Pressure at a depth is given by :
Where
is the density of air,
So,
Total pressure, P = Atmospheric pressure + 12 Pa
= 1.013 × 10⁵ Pa + 12 Pa
= 1.01 × 10⁵ Pa
Hence, the total pressure is 1.01 × 10⁵ Pa.
Answer:
The increase in the internal energy of the system is 360 Joules.
Explanation:
Given that,
Heat supplied to a system, Q = 292 J
Work done on the system by its surroundings, W = 68 J
We need to find the increase in the internal energy of the system. It can be given by first law of thermodynamics. It is given by :
So, the increase in the internal energy of the system is 360 Joules. Hence, this is the required solution.
Answer:
x = 0.0734 m = 7.34 cm
Explanation:
First we shall calculate the area of the piston:
Now, we will calculate the force on the piston due to atmospheric pressure:
Now, for the compression of the spring we will use Hooke's Law as follows:
where,
k = spring constant = 3400 N/m
x = compression = ?
Therefore,
<u>x = 0.0734 m = 7.34 cm</u>