There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as  there is more red then green in the Urn.
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Assuming that all tiles must stay whole it would be:
1×54
2×27
3×18
6×9
        
             
        
        
        
Answer:
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Step-by-step explanation:
 
        
                    
             
        
        
        
Hi! actually, the y intercept is 0, 8. hopefully this helps