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never [62]
3 years ago
15

From a group of 3 men and 4 women, a delegation of 2 is selected. What is the expected number of men in the delegation?

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:

The expected number of men in the delegation is 0.86.

Step-by-step explanation:

Number of men = 3

Number of women = 4

A delegation of 2 is selected.

Let X be the number of men selected. So, the possible values of X are 0,1,2.

P(X=0)=\dfrac{^3C_0\times ^4C_2}{^7C_2}=\dfrac{2}{7}

P(X=1)=\dfrac{^3C_1\times ^4C_1}{^7C_2}=\dfrac{4}{7}

P(X=2)=\dfrac{^3C_2\times ^4C_0}{^7C_2}=\dfrac{1}{7}

The expected number of men in the delegation is

E(x)=0\times P(X=0)+1\times P(X=1)+2\times P(X=2)

E(x)=0\times \dfrac{2}{7}+1\times \dfrac{4}{7}+2\times \dfrac{1}{7}

E(x)=\dfrac{6}{7}

E(x)\approx 0.86

Therefore, the expected number of men in the delegation is 0.86.

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A bottle weighs 1.2 kg when it is 1/4 full of water. It weighs 2.4 kg when it is full. What is the weight of the empty bottle?
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Answer:

Weight of empty bottle = 0.8 kg

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Step-by-step explanation:

As given , A bottle weighs 1.2 kg when it is 1/4 full of water. It weighs 2.4 kg when it is full.

Let us assume

Weight of empty bottle = x

Weight of water = y

Now,

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⇒ Weight of water + weight of bottle = 1.2

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⇒ Weight of water + weight of bottle = 2.4

⇒ y + x = 2.4        ......(2)

Subtract equation (2) from equation (1) , we get

y + 4x - ( y+ x) = 4.8 - 2.4

⇒ y + 4x - y - x = 2.4

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⇒x = \frac{2.4}{3} = 0.8 kg

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