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Feliz [49]
3 years ago
12

If the streets of a city are straight lines and the intersections are points, show how Principle 2 and Principle 3 might be illu

strated -(plane geometry Abeka second edition)
Mathematics
1 answer:
Naily [24]3 years ago
6 0

Step-by-step explanation:

In the plane geometry Abeka, second edition, it is given :

Principle 2 states that between any two points, only one straight line can be drawn.

And according to principle 3 two straight lines interacts at one point only.

Thus this can be well illustrated by two straight lines which are represented by the streets of a city and these two streets intersects at a point.

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muminat
Multiply both sides by 4
3w-2w-16=48
Combine like terms
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w=64
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PLEASE HELPPP <br><br> AKA JASMINE IS THE BEST PUR<br> will give brainliest
Alisiya [41]

Answer:

45/2

Step-by-step explanation:

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There are two people and there are 45 minutes to shoot the ball. As both people shoot for the exact same time, you have to divide 45 by 2 to split the time into two equal halves. Thus, the answer is 45 divided by 2, or just 45/2.

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3 years ago
Tina is five years older than her brother Tom. The sum of their ages is 51 write an equation
Serga [27]

Answer:

46+5. 5×10+1. umm idk if this is ok

4 0
3 years ago
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Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?
garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right).

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be z (x) = \cos x the base formula, where x is measured in sexagesimal degrees. This expression must be transformed by using the following data:

T = 180^{\circ} (Period)

z_{min} = -4 (Minimum)

z_{max} = 5 (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of 2\pi radians. In addition, the following considerations must be taken into account for transformations:

1) x must be replaced by \frac{2\pi\cdot x}{180^{\circ}}. (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

\Delta z = \frac{z_{max}-z_{min}}{2}

\Delta z = \frac{5+4}{2}

\Delta z = \frac{9}{2}

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

z_{m} = \frac{z_{min}+z_{max}}{2}

z_{m} = \frac{1}{2}

The new function is:

z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)

Given that z_{m} = \frac{1}{2}, \Delta z = \frac{9}{2} and T = 180^{\circ}, the outcome is:

z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

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liraira [26]

Answer:

53

Step-by-step explanation:

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