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egoroff_w [7]
2 years ago
5

Roman created the following table to represent the balance of his loan, y, over a period of months, x. The equation for the line

of best fit of Roman's table of dadt is y= -200.22x + 5,014.20.​
Mathematics
1 answer:
Ronch [10]2 years ago
4 0

Answer: extrapolation, and 25 months

Step-by-step explanation:

I took the Plato test and got it right, but if you want to know. Interpolation means based on the numbers given you could see the answer, extrapolation means you have to go farther than the last plot point given to get your answer. Which you do since it does not go past 12 months.

The second answer you can roughly get by pluging in each of the choices in the equation for x

For example: y=-200.22(25)+5015.20

That should give you an answer pretty close to zero so there is your answer

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Please can someone help
Sergeu [11.5K]
Answer = £44,918

220x8.8 = 1936
2.3x2.1 = 4.83
1936 + 4.83 = 1940.83
1940.83/1.6 = 1213.01
1214x37 = 44918
6 0
2 years ago
Please give me the correct answer.Only answer if you're very good at math.Please don't put a link to a website.​
Alexus [3.1K]

Answer:

3, 50, 2

Step-by-step explanation:

By multiplying all terms by 5, we are trying to remove the fraction on the left hand side. On the right hand side of the equation, expand the bracket by multiplying 5 to each term in the bracket.

3(n +25)= 5(10) +5(\frac{2}{5} n)

3(n +25)= 50 +2n

To find the value of n, expand the bracket on the left hand side:

3(n) +3(25)= 50 +2n

3n +75= 50 +2n

Bring all n terms to one side, constants to the other:

3n -2n= 50 -75

n= -25

8 0
2 years ago
A race walker completed a 13 mile walk in 2.5 hours. What is the walker's speed per hour?
Viktor [21]

Answer:

5.2mph

Step-by-step explanation:

Speed =distance/time

13/2.5=5.2 mph

4 0
2 years ago
Find the measure of each angle indicated. HELPPP PLEASE
anzhelika [568]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -
GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0
3 years ago
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