What is the y-intercept of the line below? :y=-1/4x +1
1 answer:
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Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Answer:
Step-by-step explanation:
From the given information;
The null hypothesis & alternative hypothesis:
The test statistics can be computed as:
The p-value = 2(Z > 2.11) since this is a two-tailed test
The p-value = 2( 1 - Z < 2.11)
The p-value = 2 (1 -0.9826)
The p-value = 2 (0.0174)
The p-value = 0.0348
Decision Rule: To reject the if the p-value is less than
Conclusion: We fail to reject and conclude that the population mean = 2, thus the machine is properly adjusted.