Angle = 68⁰ is an inscribed angles, this angle equal 68⁰,
so it intersect arc = 2*68⁰= 136⁰.
Arc of the whole circle (circumference) =360⁰,and it also =b+104+136.
b+104+136 =360
b=360-(104+136) = 120⁰
Answer A. b=120⁰.
Answer:
Number 1 I think sorry if I am incorrect.
Answer:
5/4k^2
Step-by-step explanation:
P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.
We will be using the following property of exponents:
\dfrac{a^x}{a^y}=a^{x-y}.
We have
P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.
Thus, the required product is \dfrac{5}{4k^2}.
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Step-by-step explanation:
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