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MArishka [77]
3 years ago
10

The product of a rational and irrational number is rational.

Mathematics
1 answer:
Mashutka [201]3 years ago
7 0

Answer:

What is the question?

Step-by-step explanation:

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Need to find the ratio
wolverine [178]

Answer:

B

Step-by-step explanation:

CosA = AB/AC = 12/20 = 3/5

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3 years ago
Which of the k-values satisfy the following inequality?
Arte-miy333 [17]
6>2k+4
2>2k
1>k

k has to be less than 1

Answer: a) k=0

Hope this helps:)
7 0
3 years ago
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Construct equation
ElenaW [278]

Step-by-step explanation:

(x × 5) +6=41

5x + 6=41

5x =41-6

5x=35

x=(35/5)

x=7

6 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
Allushta [10]

Answer:  proof below

<u>Step-by-step explanation:</u>

Use the Difference formula for sin:

  sin (A - B) = sin(A)·cos(B) - cos(A)·sin(B)

sin (180° - θ) = sin(180°)·cos(θ) - cos(180°)·sin(θ)

                    =       0  · cos(θ)    -      -1  · sin(θ)

                    =              0           -           -sin(θ)

                    =                         + sin(θ)

sin (180° - θ) = sin(θ)  \checkmark

8 0
3 years ago
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Depreciation is the decrease or loss in value of an item due to age, wear, or market conditions. We usually consider depreciatio
Alik [6]

Answer:The value of the bulldozer after 3 years is $121950

Step-by-step explanation:

We would apply the straight line depreciation method. In this method, the value of the asset(bulldozer) is reduced linearly over its useful life until it reaches its salvage value. The formula is expressed as

Annual depreciation expense =

(Cost of the asset - salvage value)/useful life of the asset.

From the given information,

Useful life = 23 years

Salvage value of the bulldozer = $14950

Cost of the new bulldozer is $138000

Therefore

Annual depreciation = (138000 - 14950)/ 23 = $5350

The value of the bulldozer at any point would be V. Therefore

5350 = (138000 - V)/ t

5350t = 138000 - V

V = 138000 - 5350t

The value of the bulldozer after 3 years would be

V = 138000 - 5350×3 = $121950

4 0
3 years ago
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