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Kruka [31]
3 years ago
14

The area of a trapezoid is 864cm². It has a height of 24 cm, and the length of one of its bases is 30 cm. What is the length of

the other base?​
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
5 0

The area <em>A</em> of a trapezoid with height <em>h</em> and bases <em>b</em>₁ and <em>b</em>₂ is equal to the average of the bases times the height:

<em>A</em> = (<em>b</em>₁ + <em>b</em>₂) <em>h</em> / 2

We're given <em>A</em> = 864, <em>h</em> = 24, and one of the bases has length 30, so

864 = (<em>b</em>₁ + 30) 24 / 2

864 = (<em>b</em>₁ + 30) 12

864 = (<em>b</em>₁ + 30) 12

72 = <em>b</em>₁ + 30

<em>b</em>₁ = 42

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It is given that DBCA is a quadrilateral. Since it is a quadrilateral it means the have 4 vertices and 4 angles D, B,C,A.

The angles are formed in the order of the figure name. If the quadrilateral name is DBCA, So the order of the angles are D,B,C,A. It means the angle immediate after D is B, the angle immediate after B is C, the angle immediate after C is A and the angle immediate after A is D.

If the quadrilateral name is DBCA it means the sides are DB, BC, CA and AD as shown in the figure.

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In the figure there are some types of quadrilateral and from the figure we can easily noticed that the consecutive angles with angle D are B and A.

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