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Rufina [12.5K]
3 years ago
6

Brooke has scores of 84, 72, 90, 95, and 87 on her first five quizzes. After taking the sixth quiz, Brooke’s mean score increase

d. Which could be Brooke’s sixth quiz score? Check all that apply. 85 90 83 86 92 89
Mathematics
2 answers:
OlgaM077 [116]3 years ago
7 0

Answer:

90, 86, 92, 89

Step-by-step explanation:

The mean of her first five quiz scores is found by adding the scores together and dividing by 5:

(84+72+90+95+87)/5 = 428/5 = 85.6

Any value higher than this mean for the sixth quiz score will raise the overall mean; any value below this mean for the sixth quiz score will lower the overall mean.  This means the values that could increase her mean are 90, 86, 92 and 89.

Dafna11 [192]3 years ago
6 0

Answer:

90, 86, 89, and 92

Step-by-step explanation:

Basically anything above 85.6

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(1.2×10^2) + (3.04×10^5)
PSYCHO15rus [73]

(1.2×10^2) + (3.04×10^5)

They must be to the same power to add

3.04 *10^5   to change to the 2nd power (5-2=3) move the decimal 3 places to the right = 3040. * 10^2

1.2 * 10^2   + 3040 *10^2=

add the numbers keep the exponents the same

3041.2 * 10^2

there can only be 1 number before the decimal in scientific notation so we need to move the decimal 3 places to the left, which adds 3 to the exponent

3.0412 * 10 ^ (2+3)

3.0412 * 10^5


8 0
4 years ago
The sum of two integers is 26. the sum of the squares of the two integers is 340. what is the product of the two numbers?
Phoenix [80]
Lets say that the two unknown integers are n and m.

We know the following things about n and m:

n+m=26
n^2+m^2=340

And, we want to find nm.

To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:

(n+m)^2=n^2+2nm+m^2

So, given what we know about the unknown integers, the previous can be written as:

(26)^2=340+2nm

We can easily solve for nm:

nm= \frac{(26)^2-340}{2}= \frac{676-340}{2}= \frac{336}{2}=168

The answer is 168.

Another approach to solve the problem is, from the two starting equations, compute the values of n and m, which are 12 and 14, and directly compute their product; however, the approach described is more elegant. 
5 0
3 years ago
Write an expression for 213 increased by d.
Tcecarenko [31]

Write an expression for 213 increased by d: 213+d=x

6 0
3 years ago
Your class rank in 2018 was 89 out of 360 students. In 2019 your class rank was 95 out of 450 students. a. In which year did you
spin [16.1K]

A) given that in 2019 you were among the 21.11% of the best students in the class, in that year you had the higher percentile ranking, and B) the measure of average that would be the most meaningful is the median.

Given that your class rank in 2018 was 89 out of 360 students, while in 2019 your class rank was 95 out of 450 students, to determine A) in which year did you have the higher percentile ranking, and B) if you had the data on the cumulative GPA of each student at the end of the spring semester in 2018, which measure of average would be the most meaningful - mean, median or mode -, the following calculation should be performed:

  • 360 = 100
  • 89 = X
  • 89 x 100/360 = X
  • 24.72 = X
  • 450 = 100
  • 95 = X
  • 95 x 100/450 = X
  • 21.11 = X

Therefore, A) given that in 2019 you were among the 21.11% of the best students in the class, in that year you had the higher percentile ranking, and B) the measure of average that would be the most meaningful is the median.

Learn more about maths in brainly.com/question/25748895

8 0
3 years ago
You have a combination lock with 3 secret digits. Find the 3 correct digits using the following clues and enter your answer belo
zalisa [80]

Answer:

184

Step-by-step explanation:

in the number 128 the number eight is right it should be to the right then in the number157 one is right it should be to the left in 841 8and 1 are in the wrong position 8 - right 1 - left then in the number 624 the number 4 is right but in the wrong position it should be in the middle the answer is digit 1,8,4

3 0
2 years ago
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