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3 years ago

4598(345+892•231)•5617(1232+987)/2=?

Mathematics

1 answer:

jeka57 [31]3 years ago

4 0

Answer:

$5.91430991*10^1^5$

Step-by-step explanation:

$4598\left(345+892\cdot \:231\right)\cdot \:5617\cdot \frac{1232+987}{2}\\=4598\cdot \:5617\cdot \frac{1232+987}{2}\left(345+206052\right)\\=4598\cdot \:5617\cdot \frac{2219}{2}\left(345+206052\right)\\=4598\cdot \:206397\cdot \:5617\cdot \frac{2219}{2}\\=\frac{2219\cdot \:4598\cdot \:206397\cdot \:5617}{2}\\=\frac{1.18286\dots E16}{2}\\=5.91431e15$

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Help I’ll give you 30 points

Gnesinka [82]

Answer:

a) 16.25 centimeters

b) 6.8 centimeters

Step-by-step explanation:

We can set up a proportion for both of these problems.

a) Look at the longest side of each triangle. We can set up a fraction: 7.2/18. We can also set up a fraction for XZ and PR:

6.5/x

x represents the length you're trying to find.

Since the triangles are similar, we have an equation:

7.2/18=6.5/x

Cross multiply

16.25

XZ is 16.25 centimeters long.

We can do same thing:

7.2/18=x/17

Cross multiply

6.8

QR is 6.8 centimeters long.

Hope this helps!

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3 years ago

Read 2 more answers

Which statement belongs in the intersection of the Venn Diagram? PLEASE HELP!

svetoff [14.1K]

The space within a closed figure. hope this helps

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3 years ago

At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us

wolverine [178]

Answer:

The expected value of every ticket is a loss of $ 1.35

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
Probability of 4th prize of $ 73 (75 - ticket) = 1/1,500
Probability of losing $ 2 (ticket) = 1,496/1,500

Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

Expected value = [- 2,992 +498 + 248 + 148 + 73)/1,500

Expected value = -2,025/1,500 = - 1,35

The expected value of every ticket is a loss of $ 1.35

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3 years ago

There are nine water bottles in a fridge. Three full boxes are added. Two more boxes are added, both of which have one fewer bot

Degger [83]

The number of bottles in a full box is 12.

Explanation

Suppose, the number of bottles in a full box is $x$

So, the number of bottles in three full boxes $=3x$

Now, two more boxes are added, both of which have one fewer bottle than the other three. So, the number of bottles in these two boxes $= 2(x-1)$

As there were 9 bottles initially and now there are 67 bottles in the fridge, so the equation will be....

$9+3x+2(x-1)=67\\ \\ 9+3x+2x-2=67\\ \\ 5x+7=67\\ \\ 5x=67-7\\ \\ 5x=60\\ \\ x=\frac{60}{5}=12$

Thus, the number of bottles in a full box is 12.

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3 years ago

F^(-2) = fl-4) = ff"(-2)) =

Novay_Z [31]

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6 0

3 years ago