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kotykmax [81]
4 years ago
10

Ken has made a selection of square jam sandwiches for a party, which he arranges in a single layer on the table in a perfect rec

tangle. Sarah has brought along the same number of square peanut butter sandwiches, which she puts out, also as a single layer, to form a border (one sandwich wide) around Ken’s rectangle. Given that all of the sandwiches are the same size and they are all used, how many sandwiches could each person possible have made?

Mathematics
2 answers:
Vesnalui [34]4 years ago
8 0
Perimetre + 4 = area
Each person must have made 24
svet-max [94.6K]4 years ago
4 0

Each person possibly have made 24 or 30 sandwiches.

Explanation

Lets assume, there are 'm' number of sandwiches across the length and 'n' number of sandwiches across the width of rectangle.

So, the number of sandwiches for Ken = m*n

Now Sarah is making the border of the rectangle using same size sandwiches.

So, the number of sandwiches for Sarah = m+n+m+n +4 = 2m+2n+4 (As there will be 4 extra sandwiches at four corner of the border)

The question says that both Ken and Sarah is using same number of sandwiches. So, 2m+2n+4 = m*n

This equation will be only satisfied if the values of 'm' and 'n' are either 6 and 4 or 10 and 3

If m=6 and n=4 , then each person have made (6×4)= 24 sandwiches

and if m=10 and n=3 , then each person have made (10×3)= 30 sandwiches

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malfutka [58]
I don't fully understand the question but I hope this helps...

I believe this would mean he made $1405 that day.
3 0
3 years ago
Use the triangle below to find cos V.
Semenov [28]

Answer:

cos\ V = \frac{2\sqrt{29}}{29}

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

cos\theta = \frac{Adjacent}{Hypotenuse}

In this case:

cos V= \frac{TV}{UV}

Where

TV = 6

and

UV^2 = TV^2 + TU^2 -- Pythagoras

UV^2 = 6^2 + 15^2

UV^2 = 261

Take square roots

UV = \sqrt{261

UV = \sqrt{9*29

UV = \sqrt{9} *\sqrt{29

UV = 3\sqrt{29

So:

cos V= \frac{TV}{UV}

cos\ V = \frac{6}{3\sqrt{29}}

cos\ V = \frac{2}{\sqrt{29}}

Rationalize:

cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}

cos\ V = \frac{2\sqrt{29}}{29}

8 0
3 years ago
CAN SOMEONE HELP ME UNDERSTAND THIS PLEASE
ICE Princess25 [194]

YEAH OFC SHAWTY!

  • so for A its -4^11 because if the powers have the same base and they are being multiplied you add the powers
  • For B its the same idea, they have the same base, and are being multiplied so you add the powers- 13^9
  • For C its similar, you have the same base, but since its Dividing, you subtract the powers. So, 9^5
  • for D you pretend like the denominator has a power of 1 and subtract. So its -24^5-24^1 which hopefully puts it into perspective of being -24^4 becuase we subtracted the powers

I cant do 2 right now, but i will in a minute

<u>And for 3 his mistake is that they arent the same bases so he cant add the powers, he should have converted them to the same base first. </u>

7 0
3 years ago
WILL GIVE BRAINLIEST FOR ANSWER
Bezzdna [24]

Answer:

the answe is 187 cm square

4 0
3 years ago
Read 2 more answers
70% of Ms. Miller's class passed the test on the first try. Those who failed were able to retake and half of those students pass
MrRissso [65]

Answer:

85%

Step-by-step explanation:

  1. Calculate how many students passed on their first try. 20 x 70% is 14, so 14 students passed on their first try.
  2. 6 students retook the test. Half of 6 is 3. Add 3 to the 14 students that passed earlier.
  3. Calculate the percent with the equation 17/20 = 0.85. 0.85 = 85%.
5 0
3 years ago
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