The additive inverse of a number gives zero. The additive inverse of the complex number -8+3i is 8-3i.
<h3>What is additive inverse?</h3>
The additive inverse of a number is the other number which when added to the initial number gives the output as zero.
As we know about the additive inverse, therefore, we need a number that will return zero when added to the complex number.
The additive inverse of the complex number -8+3i will be,

Thus, the additive inverse of the complex number -8+3i is 8-3i.
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The answer for your question is 3
Answer:
g(x) = | x - 2 | + 10
Step-by-step explanation:
given g(x) then g(x± h ) is a horizontal translation of g(x)
• if h > 0 then a move to the left of h units
• if h < 0 then a move to the right of h units
here the move is 2 units to the right, then
g(x) = | x - 2 |
given g(x) then g(x) + c is a vertical translation of g(x)
• if c > 0 then a move up
• if c < 0 then a move down
here the move is 10 units up , then
g(x) = | x - 2 | + 10
I have the same problem. if i find the answer i will give it to you
no it is not one x cannot have 2 y's.