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Y_Kistochka [10]
2 years ago
14

A principal of $3200 is invested at 7.75% interest, compounded annually. How much will the investment be worth after 13 years?

Mathematics
1 answer:
Sedaia [141]2 years ago
6 0

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3200\\ r=rate\to 7.75\%\to \frac{7.75}{100}\dotfill &0.0775\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &13 \end{cases} \\\\\\ A=3200\left(1+\frac{0.0775}{1}\right)^{1\cdot 13}\implies A=3200(1.0775)^{13}\implies A\approx 8444.51

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Find the quotient please
LenKa [72]

Answer:

-7.

Step-by-step explanation:

Fractions are division! If you don't know what a quotient is, It is basically a more complicated way of saying "find the answer by dividing." So we always divide the numerator (top number) by the denominator (bottom number). So we get 14÷-2 and we can see that -2 is a negative number, so remember that a positive times or divided by a negative is always a negative number. So therefore we get -7 as our quotient.

6 0
3 years ago
Jackson is starting an exercise program. The first day he will spend 30 minutes on the treadmill. He will increase his time on t
yulyashka [42]

Answer:

40 minutes.

Step-by-step explanation:

  • time spent on the thread mill as a function of d(day) = t(d)

= 30 +2(d-1) minutes

[where d represents day number]

(when d is 1 the time spent should be 30

so substitute d=1 and check it will be 30 only.

on first day he will spend 30 minutes so, I added 30 .

and on every additional day( these additional days are excluding first day), he will increase the time by 2 minutes.so, I added 2(d-1) to initial 30 minutes)

  • so, T(6), the minutes he will spend on the treadmill on day 6=

=30+2(6-1)

=30+2(5)

=30+10

=40 minutes

3 0
3 years ago
My state's lottery has 30 white balls numbered from 1 through 30 and 20 red balls numbered from 1 through 20. In each lottery dr
seropon [69]

The three whites:

(30 choose 1) * (29 choose 1) * (28 choose 1) = 30 * 29 * 28


The two reds:

(20 choose 1) * (19 choose 1) = 20 * 19


So, The three whites + two reds = 30 * 29 * 28 + 20 * 19 = 24740

7 0
3 years ago
¿De qué manera influye la ética en el hombre a partir de su función crítica? Explique.
Radda [10]

Answer:

La ética es una rama de la filosofía que se ocupa de la reflexión crítica sobre las acciones de los hombres. En un sentido general, la ética busca establecer los criterios para juzgar si una acción puede calificarse de correcta o incorrecta, y para evaluar los motivos y consecuencias de dicha acción. Las cuestiones éticas también juegan un papel importante en la política, los negocios y la medicina, y en campos de la ciencia y el estudio como la historia, la biología y la sociología, la ética de la profesión es ocasionalmente un tema de discusión.

Así, la ética implica una evaluación de las acciones de las personas, calificándolas como correctas o incorrectas a los ojos de la sociedad. De esta manera, influye en la forma en que las personas realizan o dejan de realizar una determinada acción, ya que estas consideran sus consecuencias positivas o negativas al momento de realizarla.  

7 0
3 years ago
The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
saul85 [17]

Answer:

a)0.08  , b)0.4  , C) i)0.84  , ii)0.56

Step-by-step explanation:

Given data

P(A) =  professor arrives on time

P(A) = 0.8

P(B) =  Student aarive on time

P(B) = 0.6

According to the question A & B are Independent  

P(A∩B) = P(A) . P(B)

Therefore  

{A}' & {B}' is also independent

{A}' = 1-0.8 = 0.2

{B}' = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B')  (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

P(\frac{B'}{A}) = \frac{P(B'\cap A)}{P(A)} = \frac{0.4\times 0.8}{0.8} = 0.4

Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

=\frac{P({A}'\cap {B}')}{P({B}')} = 0.4

P({A}'\cap {B}') = 0.4 x P({B}')

= 0.4 x 0.4 = 0.16

P({A}'\cap {B}') = 0.16

i)

The probability that at least one of them is on time

P(A\cup B) = 1- P({A}'\cap {B}')  

=  1 - 0.16 = 0.84

ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0
3 years ago
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