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3 years ago

Solve √(3x+7)+2√(x-8)=0.

Mathematics

1 answer:

laiz [17]3 years ago

4 0

Answer:

The solution to this question is 39

Step-by-step explanation:

Given that :

√(3x+7)+2√(x-8)=0.

√(3x+7)=-2√(x-8) (i)

square of the equation (i)

Then

(√(3x+7))^2=(-2√(x-8))^2

we know that √a*√a=(√a)^2=a So,

(3x+7)=4(x-8)

3x+7=4x-32 //multiply by 4

32+7=4x-3x exchange the value.

39=1x

x=39.

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lianna [129]

The number of permutations of the problem is

This = 24
Outfit = 360

<h2>Combination</h2>

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Combinations are the number of ways to choose members from a certain number, namely from members of a set, combinations can also be interpreted as many ways to make subsets, namely with a certain number of members, namely from members of a set, if a set has n members then the selection of r members, and the combination of n is where r is less than n.

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<h3>The Formula : </h3>

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<h2>Permutation</h2>

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Permutations are a way to determine the number of arrangements that occur by paying attention to the order. So in permutations, position/order is very important, namely AB is considered different from BA (AB ≠ BA). Permutation formula

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<h3>The Formula :</h3>

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$\frac {n!}{k!}$ (With Double Elements)

n! (Without Double Elements)

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<h2>Factorial</h2>

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The factorial of a natural number is the successive multiplication of a natural number that begins with the number one and arrives at the natural number, the factorial is used in calculating combinations, probabilities, and permutations.

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<h3>For example</h3>

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》2! = 1 × 2
》3! = 1 x 2 x 3
》4! = 1 x 2 x 3 x 4
》5! = 1 x 2 x 3 x 4 x 5
》6! = 1 × 2 × 3 × 4 × 5 × 6
》7! = 1 × 2 × 3 × 4 × 5 × 6 × 7
》8! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8
》9! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9
》10! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9 × 10

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The following is an example of a factorial that does not involve mixed arithmetic operations, so if you want to add it up we just need to calculate it like a normal number, a factorial number that only multiplies the difference between a factorial number that is added up by addition, subtraction, multiplication, division, for example see below.

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6! x2! - 3! : 4!

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The example above is a mixed arithmetic operation that contains multiplication, subtraction, and division. Remember that in mixed arithmetic operations, multiplication/division must be completed before addition/subtraction.

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<h3>The Formula : </h3>

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n! (Combined Multiplication)

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<h2>Place Filling Rules</h2>

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The Place Fill Rule is a method or method that can be used to determine the number of ways an object occupies its place. The filling slots rule is a method of calculating how many possible ways there are in an experiment or event. If a first event can be done in m different ways and the second event can be done in a different way and so on until the last event in k.

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<h3>The formula</h3>

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n1 × n2 × n3 × ... × nr

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<h2><u>Question</u></h2>

Find the number of permutations of letters of the word

- this

- outfit

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<h2><u>Answer</u></h2>

"Number One"

=》This = Four Letters ( 4! )

P = 4!

P = 1 × 2 × 3 × 4

P = 2 × 3 × 4

P = 6 × 4

P = 24

==========

"Number Two"

=》Outfit = Six Letters ( 6! )

=》Outfit = Two Letters The Same ( "T" ) = 2!

P = $\frac {1×2×3×4×5×6}{2×1}$

P = $\frac {2×3×4×5×6}{2}$

P = $\frac {6×4×5×6}{2}$

P = $\frac {24×5×6}{2}$

P = $\frac {120×6}{2}$

P = $\frac {720}{2}$

P = 360

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<h2><u>Conclusion</u></h2>

So, the number of permutations of the problem is

This = 24
Outfit = 360

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<h2>Learn More</h2>

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<h2>Answer Detail</h2>

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➽ Subject: Mathematics
➽ Class : 12
➽ Chapter : 7 - The Rule of Counting:
➽ Maple Code
➽ Categorization code : 12.2.7
➽ Keywords : This, Outfit

5 0

3 years ago