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2 years ago

Solve √(3x+7)+2√(x-8)=0.

Mathematics

1 answer:

laiz [17]2 years ago

4 0

Answer:

The solution to this question is 39

Step-by-step explanation:

Given that :

√(3x+7)+2√(x-8)=0.

√(3x+7)=-2√(x-8) (i)

square of the equation (i)

Then

(√(3x+7))^2=(-2√(x-8))^2

we know that √a*√a=(√a)^2=a So,

(3x+7)=4(x-8)

3x+7=4x-32 //multiply by 4

32+7=4x-3x exchange the value.

39=1x

x=39.

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Read 2 more answers

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jeka57 [31]

Answer:

=> Apply law of cosine

$c^2=a^2+b^2-2abcos\left(C\right)$

=> input value

$z^2=6.5^2 + 9.4^2-\left(6.5\right)\left(9.4\right)\left(cos\left(131\right)\right)$

=> simplify

$z=\sqrt{\left(6.5^2+\:9.4^2\right)-\left(6.5\right)\left(9.4\right)\left(-0.65605902899\right)}$

=> calulcation

$z=\sqrt{-61.1\cos \left(131^{\circ \:}\right)+130.61},\:z=-\sqrt{-61.1\cos \left(131^{\circ \:}\right)+130.61}$

=> apply rule: Distance must be greater than 0

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