Answer:
A) Lipid synthesis : Smooth endoplasmic reticulum.
B) Calcium ion storage : Smooth endoplasmic reticulum.
C) Poison detoxification : Smooth endoplasmic reticulum.
D) Protien synthesis : Rough endoplasmic reticulum.
E) Protien modification and sorting : Golgi apparatus
F) Cisternal maturation : Golgi apparatus.
G) Macromolecule digestion : Lysosomes
H) Autophagy : Lysosome.
Explanation:
<u>Smooth endoplasmic reticulum</u> is involved in the synthesis and storage of lipids . It also stores the calcium ions and contain enzymes responsible for the detoxification of the poisonous substances like CCL4 and other agents. SO the answer of A , B and C is Smooth endoplasmic reticulum.
<u>Rough endoplasmic reticulum</u> contains ribosomes which synthesize protiens thus answer of D is RER.
The <u>Golgi apparatus</u> functions as a factory in which the protiens recieved from the endoplasmic reticulum are modified and sorted and is also involved in cysternal maturation so answer of option E and F is Golgi apparatus.
<u>Lysosomes</u> are the part of endomembrane system involved in the digestion of the macromolecules and in the recycling of the worn-out organelles hence also involved in autophagy. Hence answers of G and H is lysosomes.
Answer:
The answer is nuclear fusion
Explanation:
Solar energy is created by nuclear fusion that takes place in the sun. Fusion occurs when protons of hydrogen atoms violently collide in the sun's core and fuse to create a helium atom.
Answer:
A water molecule consists of two hydrogen atoms attached to one of oxygen and its general structure is angular. This is because the oxygen atom, in addition to forming bonds with hydrogen atoms, has two pairs of non-shared electrons.
Answer:
6 offsprings with white fur
Explanation:
The gene involved here codes for fur colour in mice where the allele for brown fur (B) is dominant over the allele for white fur (b) i.e. the B allele will mask the expression of b allele in an heterozygous state (Bb).
Since allele B is dominant, in an heterozygous state (Bb), the mice will be brown-furred. Hence in a cross between two Bb parents, a phenotypic ratio of 1:2:1 will be produced where;
1 is BB (homozygous brown fur), 2 is Bb (heterozygotic brown fur) and 1 is bb (homozygous white fur).
Hence, 1/4 × 100= 25% offsprings will be white furred. If 24 mice result, 25/100 × 24 = 6 offsprings will be white.
