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saul85 [17]
3 years ago
10

Cual es la ecuación de la recta que pasa por el punto (1, 2) y tiene una inclinación de 71.56505118

Mathematics
1 answer:
kogti [31]3 years ago
3 0

Answer:

La inclinación de una recta esta definida como el ángulo entre el eje x positivo y la recta.

Primero, podemos escribir genéricamente una recta como:

y = p*x + s

donde p es la pendiente de la recta, y s es la ordenada al origen.

Sabemos que para una recta que pasa por los puntos (a, b) y (c, d) podemos escribir la pendiente como:

p = (d - b)/(c - a)

Y también sabemos que si θ es el ángulo de inclinación, entonces:

p = tan(θ)

Entonces en este caso sabemos que:

p = tan(71.56505118°) = -0.828

Entonces esta recta es:

y = -0.828*x + s

y sabemos que pasa por el punto (1, 2), entonces podemos remplazar esos valores en la ecuación para encontrar el valor de s.

2 = -0.828*1 + s

s = 2 + 0.828 = 2.828

La ecuación es:

y = -0.828*x + 2.828

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The minimum value for g(x)=x² - 10x + 16 is -9

<h3>How to determine the minimum value?</h3>

The function is given as:

g(x)=x² - 10x + 16

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Read more about quadratic functions at:

brainly.com/question/7784687

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HELP ASAP WILL GIVE BRAINLIEST
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