Question

find the equation of a line that passes through the points (3,7) and (5,3). Leave your answer in the form y=mx+c​

Answer 1

Answer:

y = - 2x + 13

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (3, 7) and (x₂, y₂ ) = (5, 3)

m = $\frac{3-7}{5-3}$ = $\frac{-4}{2}$ = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (3, 7), then

7 = - 6 + c ⇒ c = 7 + 6 = 13

y = - 2x + 13 ← equation of line