A closed rectangular tank measures 12 meters by 6 by 10 meters find the surface area of the tank

1 answer:

6 0

We know that
surface area of the tank=2*area of the base+perimeter of base*height

area of the base=12*6----> 72 m²
perimeter of the base=2*[12+6]----> 36 m
height=10 m
so
surface area of the tank=2*72+36*10----> 144+360----> 504 m²

the answer is
the surface area of the tank is 504 m²

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