A closed rectangular tank measures 12 meters by 6 by 10 meters find the surface area of the tank

1 answer:

6 0

We know that
surface area of the tank=2*area of the base+perimeter of base*height

area of the base=12*6----> 72 m²
perimeter of the base=2*[12+6]----> 36 m
height=10 m
so
surface area of the tank=2*72+36*10----> 144+360----> 504 m²

the answer is
the surface area of the tank is 504 m²

You might be interested in

ABCD∼EFGH AD=45 in. , EH=75 in. , and AB=30 in. What is EF ?

Marrrta [24]

EF = 50 in.

In similar figures, corresponding sides are proportional. We use the similarity statement ABCD~EFGH to write a proportion:

$\frac{AB}{EF}=\frac{AD}{EH}
\\
\\ \frac{30}{x}=\frac{45}{75}$

Cross multiply the proportion:
45*x = 75*30
45x = 2250

Divide both sides by 45:
45x/45 = 2250/45
x = 50

3 0

2 years ago

Solve the equation.<br><br> -1 2/7 ÷ 1 13/14 =

sergeinik [125]

Answer:

-4/13

Step-by-step explanation:

just using your calculator and you can get the answer.

5 0

2 years ago

Read 2 more answers

HELPPPPPPPPPPPPPPPPPPPPPPPPPP

netineya [11]

Answer:

1/25 of a mile per minute, I think

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Help on questions 11 and 15 Add and simplify if possible

Svetllana [295]

$\frac{16+x}{x^3}+\frac{7-4x}{x^3}=\frac{16+x+7-4x}{x^3}=\frac{23-3x}{x^3}\\\\======================================\\\\\frac{5}{t-1}+\frac{3}{t}=\frac{5t}{t(t-1)}+\frac{3(t-1)}{t(t-1)}=\frac{5t+3t-3}{t^2-t}=\frac{8t-3}{t^2-t}$

7 0

2 years ago

Read 2 more answers

4 quarts 2 cups − 1 quart 3 cups = ?

nevsk [136]

Answer: 2 quarts 3 cups

6 0

2 years ago