Answer:
The probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
Step-by-step explanation:
We are given that . At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs.
Mean = 
Standard deviation = 
We are supposed to find the probability that the average time 100 random students on campus will spend more than 5 hours on the internet i.e. P(X>5)
Z=0
P(X>5)=1-P(X<5)=1-P(Z<0)=1-0.5=0.5
Hence the probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
We need to get the equation in square form
We apply completing the square method
Divide all the terms by 5
Group x terms and y terms separately
By completing the square method, we take half of coefficient of x and square it
square it 
Add 1 on both sides
square it 
Add 4 on both sides
Add 6 on both sides
Now factor both parenthesis
The equation of the circle is
C 64 I hope I help you out
How much detail for the answer
Simply each equation is manipulated by the x in the way that the function is telling you to
x = a
f (a) = 8 + 2(a)^2
x = a + h
f (a + h) = 8 + 2( a + h) ^ 2
the last case is represented by two scenarios
x = a + h ... x = a/h
f (a + h) - f( a / h) =
(8 + 2(a + h) ^2) - (8 + 2(a / h)^2)
