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ki77a [65]
3 years ago
15

PLEASE HELP ASAP!! WILL MARK BAINLIEST

Mathematics
1 answer:
yawa3891 [41]3 years ago
4 0

Answer:

12 > x+5 (?) 52

Step-by-step explanation:


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-8= – 4ywhat is the answer ​
Montano1993 [528]

Answer:

2

Step-by-step explanation:

y = 2

6 0
3 years ago
Read 2 more answers
What it's "Linear Regression"?
Flauer [41]
Linear Regression is an approach for modeling the relationship between a scalar dependent variable y and one or more explanatory variables denoted x. the case of one explanatory variable is called simple linear regression
6 0
3 years ago
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What is the least common denominator of 3/4 and 15/16
Rudiy27

The least common denominator of 3/4 and 15/16 is 16.

<h3>What is Least Common Denominator?</h3>
  • When two or more fractions are given, the least common denominator is the smallest number of all common multiples of the denominators.
  • To find the least common denominator, list the multiples of both denominators until you find the smallest multiple shared by both.
  • Because 28 is the first shared multiple of 4 and 7, it must be the least common denominator of these two fractions.

So, LCD od 3/4 and 15/16:

  • 3/4 × 4/4 = 12/16
  • 15/16 × 1/1 = 15/16

Now, the denominator of both the fractions is the same which is 16.

Therefore, the least common denominator of 3/4 and 15/16 is 16.

Know more about Least Common Denominator here:

brainly.com/question/19249494

#SPJ9

8 0
1 year ago
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
4 years ago
What is the value of the expression, written in standard form.(6.6×10^-2)(3.3×10^-4)
quester [9]

1) 6.6 * 3.3 = 21.78

2) (10^ - 2 )*(10^ - 4) = 10 ^ ( -2 - 4) = 10 ^ - 6

3) result: 21.78 * 10 ^ - 6

4) to convert to standard form run the period on space to the lef and  multiply the ten base by 10 =>

2.178 * 10 ^ - 5

Answer: 2.178 * 10 ^ - 5
3 0
4 years ago
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