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Alex Ar [27]
3 years ago
8

In an inscribed quadrilateral, angles A & B are opposite angles and C & D are opposite angles. The measure of angle C =

the measure of angle D. the measure of angle A = 9x + 17 and the measure of angle B = 8x - 24 therefore the measure of angle A = _____
Measure angle B = _____

Measure angle C = _____

Measure angle D = _____
Mathematics
1 answer:
vlada-n [284]3 years ago
6 0

Answer:

<A = 116°

<B = 64°

<C = <D = 90°

Step-by-step explanation:

In an inscribed quadrilateral, The sum of opposite angles is equal to 180°

If <A and <B are and also <C and <D opposite angles then:

<A+<B = 180° and

<C+<D = 180°

If <C = <D, then

<C+<C = 180°

2<C = 180°

<C = 180°/2

<C = 90° and <D = 90°

If <A = 9x+17 and <B = 8x-24, then;

9x+17+8x-24 = 180

17x-7 = 180

17x = 187

x = 187/17

x = 11°

<A = 9(11)+17

<A = 99+17

<A = 116°

<B = 180°-116°

<B = 64°

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If you knew that f(-4)=8, then what (x,y) coordinate point must lie on the graph of y=f(x?)​
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(-4,8)

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Look at teh screenshot pls
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Hey there!

When they are asking which of them are equal we need to solve a, b, c and d and see if they match up to 6x^2-2x-20.

<u>Starting with A: </u>

Expand:

3 x 2x^2 + 3 x -x + 3 x -6

Simplify 3 x 2x^2 to 6x^2

6x^2 + 3 x -x + 3 x -6

Regroup.

6x^2 = 3x + 3 x -6

Simplify 3 x -6 to -18

6x^2 - 3x - 18

That does not match up to 6x^2-2x-20.

A is INCORRECT.

<u>Solving B:</u>

Collect like terms:

4x - 2x + 2x^2 - 20

The ones bolded are like terms.

So, we now collect them and add them.

4x^2 + 2x^2 = 6x^2

6x^2 - 2x - 20

That matches up with 6x^2-2x-20.

B is CORRECT.

<u>Solving C:</u>

Multiply the parentheses then multiply:

6x^2-12x+10x-20

Collect like terms:

6x^2 - 2x - 20

This matches up with 6x^2-2x-20.

Thus, C is CORRECT.

<u>Solving D:</u>

Multiply the terms in the parentheses by -2:

6x^2 - 2x - 2 x 10

Multiply the numbers:

6x^2 - 2x - 20

This also matches up with 6x^2 - 2x - 20 / they are <u>equal.</u>

Thus, D is also CORRECT.

<h3>Therefore, our answers are: </h3><h2><u>B, C, D </u></h2>

Thanks a ton for using Brainly! :)

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5 0
3 years ago
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