Why do moving back and forth, and moving in a circle look the same on a graph of position versus time?

Physics

1 answer:

pentagon [3]3 years ago

3 0

Answer:

one dimension of motion on a circle is "back and forth"

Explanation:

Whether the position graphs look the same or not is a function of the acceleration (and velocity), and how position is measured.

For a circle centered at the origin, uniform motion around the circle will be equivalent to sinusoidal motion in the x- or y-directions. So, that motion is equivalent to sinusoidal motion "back and forth", however it may be generated.

The "back and forth" motions of a piston in a cylinder (connected to a crankshaft), and of a pendulum, are almost sinusoidal, but not quite. Their position graphs will differ slightly from the graph of position of an object moving around a circle.

On the other hand, if the circular motion is plotted as the length of the radius versus time, it will be a constant -- not "back and forth" at all.

In short, plots of similar motion will look similar.

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An object of mass 0.50 kg is transported to the surface of Planet X where the object’s weight is measured to be 20 N. The radius

Olin [163]

Answer:

$g'=40\ m.s^{-2}$

Explanation:

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radial distance between the planet and the object, $r=2\times 10^6\ m$

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4 years ago

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suppose that two objects attract each other with a gravitational force of 32 newtons. if the distance between the two objects is

grandymaker [24]

Taking into account the Universal Law of Gravitation, the force of attraction between the tow objects is 8 N.

<h3>Universal Law of Gravitation</h3>

The Universal Law of Gravitation establishes that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.

The Universal Law of Gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them.

Mathematically it is expressed as follows:

$F=G\frac{Mm}{d^{2} }$

where:

G is the universal gravitational constant, with a value of 6.67×10⁻¹¹ $\frac{Nm^{2} }{kg^{2} }$ .
M and m are the masses of the bodies that interact.
d is the distance that separates them.

<h3>Force of attraction in this case</h3>

In this case, two objects attract each other with a gravitational force of 32 newtons. The distance between the two objects is doubled.

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.

Then, if the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (d²= 2²= 4). The new force is then $\frac{1}{4}$ of the original: