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alexira [117]
3 years ago
9

An object of mass 0.50 kg is transported to the surface of Planet X where the object’s weight is measured to be 20 N. The radius

of the planet is 4.0 x 10^6 m. What free fall acceleration will the 0.50-kg object experience when transported to a distance of 2.0 x 10^6 m from the surface of this planet?
Physics
2 answers:
Olin [163]3 years ago
8 0

Answer:

g'=40\ m.s^{-2}

Explanation:

Given:

  • mass of the object, m=0.5\ kg
  • weight of the object on planet x, W=20\ N
  • radius of the planet, R=4\times10^6\ m
  • radial distance between the planet and the object, r=2\times 10^6\ m

<u>Now free fall acceleration on planet X:</u>

W=m.g'

20=0.5\times g'

g'=40\ m.s^{-2} irrespective of the height.

sveticcg [70]3 years ago
3 0

Answer:

17.78 m/s^2

Explanation:

m = 0.5 kg

Weight on the planet, W = 20 N

Acceleration due to gravity on the surface of planet, g = W / m

g = 20 / 0.5 = 40 m/s^2

Radius of planet, r = 4 x 10^6 m

height, h = 2 x 10^6 m

Let the acceleration due to gravity at a height is g'.

According to the formula of acceleration due to gravity at height is

g' = g\frac{R^{2}}{(R+h)^{2}}

g' = 40\frac{\left (4\times 10^6  \right )^{2}}{(4+2)^{2}\times 10^{12}}

g' = 17.78 m/s^2

Thus, the acceleration due to gravity at height is  17.78 m/s^2 .

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