1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
valina [46]
3 years ago
6

At room temperature, sound travels at a speed of about 344 m/s in air. You see a distant flash of lightning and hear the thunder

arrive 8.0 seconds later.
Part A) How many miles away was the lightning strike? (Assume the light takes essentially no time to reach you.)
Physics
2 answers:
Tems11 [23]3 years ago
7 0

Answer:

0.854miles away

Explanation:

The relationship between the speed of the sound (v), the distance between the sound of thunder and the reflector (x) and the time (t) can be expressed as 2x = vt

Given the speed of sound = 344m/s

time = 8.0s

x = ?

Substituting this values into the formula to get x, we have;

2x = 344(8)

x = 344×8/2

x = 1376m

Converting this distance to miles

0.000621miles = 1m

x = 1376m

x = 1376×0.000621

x = 0.854miles

The lightening strikes 0.854miles away.

bearhunter [10]3 years ago
4 0

Answer:

<em>The lighten travels 0.853 miles.</em>

Explanation:

Sound: Sound is a form of wave which is conveyed through an elastic medium from a vibrating body to a listener.

v = 2x/t .......................................... Equation 1

making x the subject of the equation

x = vt/2........................................ Equation 2

Where v = velocity of sound in air, x = distance traveled by the sound, t = time

Given: v = 344 m/s t = 8 s

Substituting into equation 2

x = 344(8)/2

x = 1376 m.

x = 1376×0.00062 miles = 0.853 miles

<em>Thus the lighten travels 0.853 miles.</em>

You might be interested in
If an egg person starts from rest then falls directly downward and hits the ground with a velocity of 12 m/s but
Anni [7]

Answer:

Explanation: Determine the gravitational acceleration. ...

Decide whether the object has an initial velocity. ...

Choose how long the object is falling. ...

Calculate the final free fall speed (just before hitting the ground) with the formula v = v₀ + gt

6 0
2 years ago
Read 2 more answers
A diver leaves the end of a 4.0 m high diving board and strikes the water 1.3s later, 3.0m beyond the end of the board. Consider
shutvik [7]

Answer:

4.0 m/s

Explanation:

The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.

Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is

d=v_x t

where here we have

d = 3.0 m is the horizontal distance covered

vx is the horizontal velocity

t = 1.3 s is the duration of the fall

Solving for vx,

v_x = \frac{d}{t}=\frac{3.0 m}{1.3 s}=2.3 m/s

Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by

y(t) = h + v_y t - \frac{1}{2}gt^2

where

h = 4.0 m is the initial height

vy is the initial vertical velocity

We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy

0=h+v_y t - \frac{1}{2}gt^2\\v_y = \frac{0.5gt^2-h}{t}=\frac{0.5(9.8 m/s^2)(1.3 s)^2-4.0 m}{1.3 s}=3.3 m/s

So now we can find the magnitude of the initial velocity:

v=\sqrt{v_x^2+v_y^2}=\sqrt{(2.3 m/s)^2+(3.3 m/s)^2}=4.0 m/s

4 0
4 years ago
What kind of research in teaching of physical science can be done???​
11Alexandr11 [23.1K]

Answer:

Physical sciences are those academic disciplines that aim to uncover the underlying laws of nature - often written in the language of mathematics. It is a collective term for areas of study including astronomy, chemistry, materials science and physics.

Explanation:

3 0
3 years ago
A girl rides her bike 5.4 km due east. While riding she experiences a resistive force from the air that has a magnitude of 3.1 N
kotegsom [21]

Answer:

(A) = 34,560 J

(B) Work done during the round trip is not zero, hence the resistive force is not a conservative force.

Explanation:

This question is incomplete, here is the complete question:

A girl rides her bike 5.4 km due east. While riding she experiences a resistive force from the air that has a magnitude of 3.1 N and points due west. She then turns around and rides due west, back to her starting point. The resistive force from the air on the return trip has a magnitude of 3.3 N and points due east.? (a) Find the work done by the resistive force during the round trip. (b) Based on your answer to part (a), is the resistive force a conservative force? Explain.

SOLUTION:

distance covered by the girl due east (De) = 5.4 km = 5400 m

magnitude of resistive force by the air (Fw) = 3.1 N due west

distance covered by the girl due west (Dw) = 5.4 km = 5400 m

magnitude of resistive force by the air (Fe) = 3.3 N due east

(A) to find the work done by the resistive force during the round trip we have to get the work done by the resistive force due west and add it to the work done by the resistive force due east

  • work done by the resistive force due west = (Fw.cosθ) x De

        where θ is the angle between the displacement and the force. The    

        displacement is due east while the force is due west, hence θ = 180°

       work done (W1) = (3.1 x cos 180) x 5400 = -16,740 j

  • work done by the resistive force due east = (Fe.cosθ) x Dw

        where θ is the angle between the displacement and the force. The    

        displacement is due west while the force is due east, hence θ = 180°

       work done (W2) = (3.3 x cos 180) x 5400 = -17,820 j

Hence work done during the round trip = W1 + W2 = (-16,740 ) + (-17,820)

= 34,560 J

(B) A conservative force is a force in which the work done by the force in moving an object around a closed path is zero. From part (A) above the work done during the round trip is not zero, hence the resistive force is not a conservative force.

3 0
3 years ago
Sound enters the ear, travels through the auditory canal, and reaches the eardrum. The auditory canal is approximately a tube op
Juliette [100K]

Answer:

The fundamental frequency of can is 2.7 kHz.                          

Explanation:

Given that,

A typical length for the auditory canal in an adult is about 3.1 cm, l = 3.1 cm

The speed of sound is, v = 336 m/s

We need to find the fundamental frequency of the canal. For a tube open at only one end, the fundamental frequency is given by :

f=\dfrac{v}{4l}\\\\f=\dfrac{336}{4\times 3.1\times 10^{-2}}\\\\f=2709.67\ Hz\\\\f=2.7\ kHz

So, the fundamental frequency of can is 2.7 kHz. Hence, this is the required solution.

7 0
3 years ago
Other questions:
  • You push a table 8 meters for 16 minuutes and do 6720 j of work how much power do ypu use
    15·1 answer
  • If 20 beats are produced within a single second, which of the following frequencies could possibly be held by two sound waves tr
    12·2 answers
  • Define fission and give an example of a reaction
    7·2 answers
  • True or false Scientific conclusions can and should be based on more than just observable evidence.
    10·1 answer
  • Which of these best describes how the kinetic energy of carbon dioxide molecules change as the carbon dioxide is heated? (2 poin
    10·2 answers
  • Why do raindrops fall with a constant speed during the later stages of their descents?
    6·1 answer
  • Consider a car moving with a constant velocity of 90 m/s. What is it’s acceleration.
    8·2 answers
  • Estimate the weight of 25 km of gas pipeline, DN = 610 mm and wall thickness = 12.7 mm.
    10·1 answer
  • Two blocks with mass M and 3M on a horizontal frictionless surface are pushed together and compress a spring of negligible mass
    7·1 answer
  • Please help me with this
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!