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valina [46]
2 years ago
6

At room temperature, sound travels at a speed of about 344 m/s in air. You see a distant flash of lightning and hear the thunder

arrive 8.0 seconds later.
Part A) How many miles away was the lightning strike? (Assume the light takes essentially no time to reach you.)
Physics
2 answers:
Tems11 [23]2 years ago
7 0

Answer:

0.854miles away

Explanation:

The relationship between the speed of the sound (v), the distance between the sound of thunder and the reflector (x) and the time (t) can be expressed as 2x = vt

Given the speed of sound = 344m/s

time = 8.0s

x = ?

Substituting this values into the formula to get x, we have;

2x = 344(8)

x = 344×8/2

x = 1376m

Converting this distance to miles

0.000621miles = 1m

x = 1376m

x = 1376×0.000621

x = 0.854miles

The lightening strikes 0.854miles away.

bearhunter [10]2 years ago
4 0

Answer:

<em>The lighten travels 0.853 miles.</em>

Explanation:

Sound: Sound is a form of wave which is conveyed through an elastic medium from a vibrating body to a listener.

v = 2x/t .......................................... Equation 1

making x the subject of the equation

x = vt/2........................................ Equation 2

Where v = velocity of sound in air, x = distance traveled by the sound, t = time

Given: v = 344 m/s t = 8 s

Substituting into equation 2

x = 344(8)/2

x = 1376 m.

x = 1376×0.00062 miles = 0.853 miles

<em>Thus the lighten travels 0.853 miles.</em>

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Please, see the attached figure for a better understanding of the problem.

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The position and velocity vectors of the salmon at a time t, can be calculated as follows:

r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)

v = (v0x, v0y + g · t)

Where:

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x0 = initial horizotal position.

v0x = initial horizontal velocity.

t = time.

y0 = initial vertical position.

v0y = initial vertical velocity.

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Looking at the figure, notice that at the maximum height, the vertical velocity is zero (because the velocity vector is horizontal). Using the equation of the vertical component of the velocity, we can obtain the time at which the salmon is at its maximum height:

vy = v0y + g · t

To find the initial vertical velocity, v0y, let´s look at the figure. Notice that the initial velocity is the hypotenuse of the triangle formed with the horizontal velocity and the vertical velocity. Then:

v0² = v0x² + v0y²

Solving for v0y:

v0y = √(v0² - v0x²)

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v0y = 6.55 m/s

Now, using the equation of the vertical component of the velocity at the maximum height (vy = 0):

vy = v0y + g · t

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y = 2.19 m

The maximum height that the fish can jump is 2.19 m.

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