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choli [55]
3 years ago
6

For f(x) = x^2, find f(4 - sqrt(2))

Mathematics
1 answer:
ryzh [129]3 years ago
4 0
\bf f(x)=x^2\qquad f(4-\sqrt{2})\implies x=4-\sqrt{2}
\\\\\\
f(4-\sqrt{2})=\left( 4-\sqrt{2} \right)^2\implies f(4-\sqrt{2})=\left( 4-\sqrt{2} \right)\left( 4-\sqrt{2} \right)

do a FOIL on it to get the product, or just use the binomial theorem to expand the binomial and simplify
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For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?
kvv77 [185]

Answer: Option C

f(x) = x^2;\ k (x) = x ^ 2 -7

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

k (x) = f (x) + b

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

f (x) = x ^ 2

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7.

Then the function k(x) that will have its vertex 7 units below f(x) is

k (x) = x ^ 2 -7

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3 years ago
What is 14 2/5 divided 3/8
satela [25.4K]
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Answer:

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Use point-slope form to find the equation of the line passing through (0,5) with a slope of 2/3
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Explanation:

Point slope form:

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