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3 years ago

A triangle has side lengths 10, 15, and 7. Is the triangle acute, obtuse, or right? Show your work and explain

Mathematics

1 answer:

Deffense [45]3 years ago

3 0

Right because if you make a triangle like that than you make a right a right angle

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A floor is 7 m long and 5 m wide. A square carpet of side 4 m is laid on the floor. Find

romanna [79]

Answer:

the area of the floor that is not carpeted 19 m squared

Step-by-step explanation:

7x5 =35 m squared = area of the floor

4x4 = 16 squared =(area of the carpeted floor)

35-16 = 19

3 0

3 years ago

Given h(x) =1/2 x + 4 find h(-4) + 2.

Lynna [10]

Hi there! :)

$\large\boxed{h(-4) + 2 = 4}$

h(x) = 1/2x + 4

Substitute in -4 for "x" to solve for h(-4):

h(-4) = 1/2(-4) + 4

h(-4) = -2 + 4

h(-4) = 2

Since we are solving for h(-4) + 2, add:

2 + 2 = 4.

8 0

3 years ago

Read 2 more answers

Find the value of x this question is for geometry please help

never [62]

5x+15 = 6x-10

Subtract 5x from 6x which leaves you with 15 = x-10

Now you add 10 to both sides of the equal sign. 25 =

x=25

7 0

4 years ago

Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> (1 point)

sesenic [268]

Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

<u>Step-by-step explanation:</u>

We have , two vectors u = <-5, -4>, v = <-4, -3> or , $u = -5i-4j , v=-4i-3j$

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

$u.v =|u|(|v|)cosx$ , where x is angle between u & v !

⇒ $u.v =|u|(|v|)cosx$

⇒ $cosx =\frac{u.v}{|u|(|v|)}$

Now , $u.v = (-5i-4j)(-4i-3j)$

⇒ $u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)$

⇒ $u.v = 20+12$ { $i(j) = j(i) =0$ }

⇒ $u.v = 32$

Now , Modulus of any vector $r = xi+yj$ is $|r| = \sqrt{x^{2}+y^{2}}$ So ,

$|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5$

Putting all these values in equation $cosx =\frac{u.v}{|u|(|v|)}$ we get:

⇒ $cosx =\frac{32}{5(\sqrt{41})}$

⇒ $cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})$

⇒ $x =cos^{-1}(1)$ { $cos0 = 1$ }

⇒ $x =0$ °

Therefore , Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

8 0

3 years ago

A solution to 8 = -x + 10 is 2

artcher [175]

Answer:

"A solution to 8 = -x + 10 is 2" is the only correct option.

3 0

2 years ago