Answers:
1.)
C - Final exams: midterm = Q3 92 - Q1 80 = 12 and finals = Q3 85 - Q1 78 = 7, so finals exam has the smaller IQR.
2.)
B - exam median is much higher than the class median: refer to the attached image of class and exam box and whisker graph
3.)
A - <span>
IQR is a better measure of spread for movies than it is for basketball games: because the data for movies are quite wide or apart from each other than the data in the basketball games
4.)
A - </span><span>
mean for April is higher than October's mean: mean in April is 67 and mean in October is 60
5.)
A - </span><span>
Neither data set has suspected outliers: meaning there's no data that is further apart from the group or set
6.)
B - </span>
There is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical
<span>
7.)
C - </span>
college spread is best described by the IQR. The high school spread is best described by the standard deviation: this is because of the wide range of data in the college than the data in the high school.
Answer:
9. m(YZ) = 102°
10. m(JKL) = 192°
11. m<GHF = 75°
Step-by-step explanation:
9. First, find the value of x
4x + 3 = 3x + 15 (inscribed angle that are subtended by the same arc are equal based on the inscribed angle theorem)
Collect like terms
4x - 3x = -3 + 15
x = 12
4x + 3 = ½(m(YZ)) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Plug in the value of x
4(12) + 3 = ½(m(YZ))
48 + 3 = ½(m(YZ))
51 = ½(m(YZ))
Multiply both sides by 2
51*2 = m(YZ)
102 = m(YZ)
m(YZ) = 102°
10. First, find the value of x.
7x + 5 + 6x + 6 = 180° (opposite angles in an inscribed quadrilateral are supplementary)
Add like terms
13x + 11 = 180
13x = 180 - 11
13x = 169
x = 169/13
x = 13
7x + 5 = ½(m(JKL)) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Plug in the value of x
7(13) + 5 = ½(m(JKL))
96 = ½(m(JKL))
Multiply both sides by 2
2*96 = m(JKL)
m(JKL) = 192°
11. First, find x.
5x + 15 = ½(11x + 18) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Multiply both sides by 2
2(5x + 15) = 11x + 18
10x + 30 = 11x + 18
Collect like terms
10x - 11x = -30 + 18
-x = -12
Divide both sides by -1
x = 12
m<GHF = 5x + 15
Plug in the value of x
m<GHF = 5(12) + 15
m<GHF = 60 + 15
m<GHF = 75°
Answer:
The time t is the independent variable while the volume V is the dependent variable
Step-by-step explanation:
A variable is a parameter that changes.
We have two types namely dependent and independent variables.
A dependent variable is a variable which its value needs to be determined based on the value of another variable while and independent variable is a variable which its value independent of other parameters.
In our question, It takes 1 hour (t) to fill the water tank of volume (V) 750 m3.
The volume of the tank V changes as time changes. So the volume of the tank V is dependent on time, t.
So V is proportional to t
Since the volume of the tank is the variable that needs to be determined based on another variable-which is time,t- it is the dependent variable, while the time,t is the independent variable since its value is not determined based on other parameters.
.95 in decimal form and 95/100 as a fraction or 19/20
Answer:
Step-by-step explanation:
2800: 2 * 2 * 2 * 2 * 5 * 5 * 7
75: 3 * 5 * 5
168: 2 * 2* 2 * 3 * 7
It's not really multiplication. It's more division.
Try 2800 as a sample. What you are trying to do is break this down into primes. The first prime is 2
2800/2 = 1400
1400 / 2 = 700
700 / 2 = 350
350 / 2 = 175. That's the end of what the 2s can do.
175 / 5 = 35
35/ 5 = 7 7 is a prime. You are done. Now run up the ladder.
2800: 2 * 2 * 2 * 2 * 5 * 5 * 7
75 is not an even number. It has no 2s. Go to 3
75 / 3 = 25.
25 / 5 = 5
That's the end
75: 3 * 5 * 5
Your calculator can be of great help. The rule is keep factoring until you get a decimal remainder. Move on to the next prime. Stop when the last division gives you a prime.