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2 years ago

WILL. GIVE BRAINLIEST IF RIGHT!!

Mathematics

1 answer:

Natali [406]2 years ago

3 0

Answer:

The class and exam medians are almost the same.

Step-by-step explanation:

The median of a box-and-whisker plot is the line inside the box.

• As we can see, the medians of class and median are very similar, both around 85. This is why the first option is correct.

•The second option is incorrect because the exam median is not much higher than the class median; the difference is very small.

• The third option is incorrect because exam does not have the lowest median. In fact, exam median is slightly higher than class median.

• The fourth option is incorrect because outliers do not affect the median.

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So its 8p = 56 is the frist bit and the second is 7. BOOM

Mice21 [21]

p=7, I don't know if this is a question or not

7 0

3 years ago

Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

3 years ago

Given: ZBECis a right angle Prove: ZAEB and ZCED are complementary

MrRissso [65]

2x77}{x} theis way is the best answee

8 0

3 years ago

The sum of (3 - 5i) + (-2 + 8i) is

andreyandreev [35.5K]

Answer:

Answer is below

Step-by-step explanation:

3−5i−2+8i

=1+3i

8 0

3 years ago

Multiply. (3b-5) (7b+1) Simplify your answer.

mylen [45]

<h3>Answer:</h3>

It would be 21b² -32b -5

<h3>Step-by-step explanation:</h3>

By using the FOIL method, you can simplify the equation.

The Foil Method is ac + ad + bc +bd, or First, Outer, Inner, Last.

First, you multiply the first term in each bracket.

3b * 7b = 21b²

Next, you multiply the outer term in each bracket.

3b * 1 = 3b

Then, you multiply the inner term in each bracket.

-5 * 7b = -35b

After that, you multiply the last term in each bracket.

-5 * 1 = -5

Lastly, you combine like terms.

21b² + 3b -35b -5 ---> 21b² -32b -5

21b² -32b -5 would be your answer, since you cannot simplify the equation anymore.

7 0

3 years ago

WILL. GIVE BRAINLIEST IF RIGHT!!​

WILL. GIVE BRAINLIEST IF RIGHT!!