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Oksi-84 [34.3K]
3 years ago
11

Find absolute max and min on a given interval calculator

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0
Min {sin(x) | 0 is les than or equal to x less than or greater than or equal to 2 pie = -1 at x = 3 pie over 2

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Mrs. Ibara wrote three decimal numbers on the board followed by two blank spaces. Complete the sequence 4.15, 6.3, 8.45 , _____,
Ket [755]
The three decimals that Mrs. Ibara wote were
4.15, 6.30 and 8.45
Now we have to find the other two numbers that are kept blank.
For this purpose, firstly we have to subtract the first 2 decimal numbers and find out the difference.
6.30 - 4.15 = 2.15
Now let us check the difference between the second and the third decimals.
8.45 - 6.30 = 2.15
So the difference is again the same. Then the fourth number will be
8.45 + 2.15 = 10.6
The fifth number will be
10.6 + 2.15 = 12.75
The blank spaces will be 10.6 and 12.75.

5 0
3 years ago
How do you graph y=2sin(x-pi)+1
Semenov [28]
Here's is a graph of that function. The 2 is the amplitude of the graph. Meaning the difference from top to bottom is 2, 3-1 is 2

The +1 moves the whole graph up one unit and the minus pi shifts the whole graph left by a length of pi.

4 0
3 years ago
Given: segment PT || segment QS, segment PT ≅ segment QS, ∠T ≅ ∠S<br> Prove: ΔPQT ≅ ΔQRS
vfiekz [6]

Segment PT || segment QS,                                  Given

segment PT ≅ segment QS,  

∠T ≅ ∠S

 

Angle TPQ = Angle SQR                      PR is a transversal  cutting parallel segments SQ and TP

                                                             So....it makes corresponding angles TPQ and SQR equal    

 

ΔPQT   ≅    ΔQRS                                ASA congruency

4 0
3 years ago
Hello, I do not anderstand this at all. I have been working on radicals and stuff, but this goes way above my head. Please help.
liraira [26]

Answer:

x = \frac{5}{7}

Step-by-step explanation:

We can start simplifying this equation by expanding the parenthesis and cross multiplying.

(7^x)^4 = \frac{7^2 * 7^3}{7^{3x}} = \\\\\\7^{4x} = \frac{7^5}{7^{3x}}\\\\\\7^5 = 7^{7x}\\\\\\

The exponent 5 and 7x are equal:

\longmapstoDivide both sides by 7

5 = 7x\\\\x = \frac57

-Chetan K

6 0
2 years ago
Read 2 more answers
What equation can fix this?
aleksandr82 [10.1K]

fix what wheres the photo of it idsi

4 0
2 years ago
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