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yarga [219]
2 years ago
10

Find the mean proportional for each pair. SHOW YOUR SOLUTION 1. 6, 24

Mathematics
1 answer:
Bingel [31]2 years ago
5 0

Answer:

The mean proportional of 6, and 24 will be 12

Step-by-step explanation:

We know that the Mean proportional of two

numbers, x, and y :  \sqrt{xy}

Therefore, the mean proportional of 6, and 24

=\sqrt{6\times 24}

=\sqrt{144}

\mathrm{Factor\:the\:number:\:}\:144=12^2

=\sqrt{12^2}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a

\sqrt{12^2}=12

=12

Therefore, the mean proportional of 6, and 24 will be 12.

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D is the midpoint of AC. If AD = 2x + 6 and DC = 4x-7, what is the length of DC?
DENIUS [597]
A----------D----------C

AD = 2x + 6
DC = 4x - 7

the midpoint D splits AC into 2 equal parts....therefore, AD = DC

2x + 6 = 4x - 7
2x - 4x = -7 - 6
-2x = - 13
x = -13/-2
x = 6.5 

DC = 4x - 7......4(6.5) - 7 = 19 <===
AD = 2x + 6.....2(6.5) + 6 = 19
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3 years ago
Which of the following would correctly fill in the blank on the following statement? 1.7 x 10__ = 0.00017
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The blank should be the power of -4, so the statement is 1.7 x 10^-4 = 0.00017.
8 0
3 years ago
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1/2 or (1/2)² which value is greater​
Ket [755]

Answer:

when a expression is squared (²) that means it is multiplyed by itself.

Step-by-step explanation:

(1/2)² = (1/2 x 1/2)

1 squared = 1

2 squared = 4

1/4 is smaller than 1/2. 1/2 is greater than (1/2)²

3 0
3 years ago
And the last question is:
Leya [2.2K]
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2 years ago
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Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with
worty [1.4K]

Answer:

z

Step-by-step explanation:

Assuming this complete question:

"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean \mu =26 kilograms and standard deviation \sigma=4.2 kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.

X"

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(26,4.2)  

Where \mu=26 and \sigma=4.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.

We can convert the corresponding z score for x=42.6 like this:

z=\frac{42.6-26}{4.2}=3.95

So then the corresponding z scale would be:

z

7 0
2 years ago
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