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Alexeev081 [22]
3 years ago
6

The figure shows a parallelogram inside a rectangle outline: A parallelogram is shown within a rectangle. The length of the rect

angle is 1 over 2 foot and the width of the rectangle is 1 over 3 foot. The two equal bases of the triangles outside the parallelogram are labeled 1 over 6 foot. What is the area of the parallelogram? 1 over 9 square foot 1 over 6 square foot 1 over 5 square foot 1 over 3 square foot

Mathematics
1 answer:
slavikrds [6]3 years ago
7 0
To find the area of the parallelogram you will need to find the distance of the base which is part of the length of the rectangle. To find this distance you will subtract 1/2 and 1/6. The height of the parallelogram is the same as the width of the rectangle.

Please see the attached picture for the work and a visual representation.

The answer is 1/9 ft.² .

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e) sec = \frac{1}{cos}   ⇒   sec \frac{7\pi}{4} = \frac{2}{\sqrt{2} } = \frac{2}{\sqrt{2} }(\frac{\sqrt{2}} {\sqrt{2}}) = \frac{2\sqrt{2} }{2} = \sqrt{2}

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Answer: (a) \frac{3\pi}{2} (b) (0, -1) (c) A (d) -1

<u>Step-by-step explanation:</u>

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b) \frac{3\pi}{2} is on the Unit Circle at (0, -1)

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