Answer:
The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

93% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
Answer:
Hello, mizuki here to help!
The correct answer would be C
Step-by-step explanation:
Ok, so the total of homework he got was 50, and the number of homework he got in monday was 16.
So.... it should be expressed as 16/50 which would be 0.32
Answer:
x > 1/9
Step-by-step explanation:
Given that:
3x-1>-6x
Adding 6x + 1 on both sides we get
3x-1 + 6x + 1>-6x + 6x +1
3x + 6x > 1
Adding both variables
9x > 1
Dividing both sides b 9 we get
9x/9 > 1/9
x > 1/9
I hope it will help you!
0.73% because you just take 100 minus 27 then add your decimal