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Goshia [24]
3 years ago
10

If the measure of Angle AXC=8x-7 and Angle AXB = 3x+10 find the measure of ANGLE AXC

Mathematics
2 answers:
mafiozo [28]3 years ago
8 0
I’m to lazy to figure out this question
s2008m [1.1K]3 years ago
5 0

Answer: you lazy is is <DXA.

Step-by-step explanation:

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3 years ago
U divided by 3 = 6 what is U a solution to
drek231 [11]

Answer:

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Step-by-step explanation:

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3 years ago
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A circle has a sector with area 33 pi and a central angle of 11/6 pi radians. What is the area of a circle?
Mashutka [201]

Answer:

36π

Step-by-step explanation:

The area of a circle is given as:

A = \pi r^2

where r = radius of the circle

The area of a sector of a circle is given as:

A_s = \frac{\alpha }{2\pi} * \pi r^2

where α = central angle in radians

Since \pi r^2 is the area of a circle, A, this implies that:

A_s = \frac{\alpha }{360}  * A

A circle has a sector with area 33 pi and a central angle of 11/6 pi radians.

Therefore, the area of the circle, A, is:

33 \pi = \frac{\frac{11 \pi}{6} }{2 \pi} * A\\\\33\pi = \frac{11}{12} * A\\\\=> A = \frac{33\pi * 12}{11}\\ \\A = \frac{396 \pi}{11} \\\\A = 36\pi

The area of the circle is 36π.

5 0
3 years ago
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