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Anika [276]
3 years ago
6

Find f(-3) if f(x) = x 2

Mathematics
1 answer:
kobusy [5.1K]3 years ago
8 0

Answer:

The value of given function for x = - 3 is 9

Step-by-step explanation:

Given as :

The y is the function of x is as

f( x ) = x²

So, For any value of x , the value of f( x ) should change

If, x = - 3

So, f ( - 3 ) = ( - 3 )²

Or, f ( - 3 ) = ( - 3 ) × ( - 3 )

i.e f ( - 3 ) = ( - × - ) ( 3 × 3 )

Or, f ( - 3 ) = ( + ) ( 9 )

∴ f ( - 3 ) =  9

So, The value of function  f ( - 3 ) =  9

Hence , The value of given function for x = - 3 is 9  Answer

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\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\

\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\

\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2}  \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625

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