The answer is C I just took the test
Answer:
1437.33
Step-by-step explanation:
Answer:
The sample data confirm the geneticist's prediction that 75% of the offspring from this cross will have red flowers.
Step-by-step explanation:
A Chi-square goodness of fit test can be used to test the claim made by the geneticist.
The hypothesis is defined as:
<em>H₀</em>: There is no difference between the observed and expected value,i.e. <em>p</em>₁ < 0.75.
<em>Hₐ</em>: There is a significant difference between the observed and expected value, i.e. <em>p</em>₁ > 0.75.
The test statistic is:

Consider the tables attached below.
The value of the test statistic is:

The critical value is:

*Use a Chi-square table.
The critical region is:

The test statistic value of 25.8133 lies in the critical region.
The null hypothesis is rejected at 1% level of significance.
<u>Conclusion</u>:
As the null hypothesis is rejected it can be concluded that 75% of the offspring from this cross will have red flowers.
X is 125 as well because it’s an Cubs all sides are equal
Answer: A:60%
Step-by-step explanation:
Since the scores for a golf tournament are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = scores for the tournament.
µ = mean score
σ = standard deviation
From the information given,
µ = 210
σ = 80
We want to find the probability percent of golfers that scored less than Ella. It is expressed as
P(x < 230)
z = (230 - 210)/80 = 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.5987
Therefore, the percent of golfers that scored less than Ella is
0.5987 × 100 = 59.87
Approximately 60%